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Nickyan · 2022年04月19日

请问答案中的0.2249是哪里来的

NO.PZ2015120604000147

问题如下:

Here is a table discribing sample statistics from two bonds' rate of return which are both normally distributed over the past decades. If an investor is considering whether the mean of bond B is greater than 26%,

which of the following conclusion is least appropriate (significant level=5%) ?

选项:

A.

It is approptiate to use the Z-test.

B.

The mean of bond B is not significant greater than 26%.

C.

It is a one-tailed test.

解释:

B is correct.

It is appropraite to ues the one-tailed Z-test because the sample size of bond B is bigger than 30.

The null hypothesis is: H0: μ 26%

The test statistic:Z=X-μSxn =(0.32-0.26)0.2249=1.91

 α= 5% indicates the critical value is equal to ±1.65.

Because 1.91>1.65, therefore, we should reject the null hypothesis.

请问答案中的0.2249是哪里来的

2 个答案

星星_品职助教 · 2022年04月19日

同学你好,

此处应为0.22 / 根号49,即计算标准误。

Vicky · 2022年04月19日

同学,你好! 答案中的0.2249是说标准差和样本数量 计算z分布的检验统计量公式是 样本均值-检验值作为分子 分母是标准差除以样本数量的开方值 分子=0.06 分母=0.22/49的开根 结果等于1.91应该是拒绝原假设 希望我的回答能够帮助到你

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