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sparkle · 2022年02月11日

这个题是不是应该放在中心极限定理部分?

NO.PZ2017092702000107

问题如下:

A population has a non-normal distribution with mean µ and variance σ2. The sampling distribution of the sample mean computed from samples of large size from that population will have:

选项:

A.

the same distribution as the population distribution.

B.

its mean approximately equal to the population mean.

C.

its variance approximately equal to the population variance.

解释:

B is correct.

Given a population described by any probability distribution (normal or nonnormal) with finite variance, the central limit theorem states that the sampling distribution of the sample mean will be approximately normal, with the mean approximately equal to the population mean, when the sample size is large.

给定具有有限方差的任何概率分布(正态或非正态)描述的总体,中心极限定理指出,当样本大小足够大的收,样本均值为正态分布,其中样本均值等于总体均值。

这个题是不是应该放在中心极限定理部分?

3 个答案

袁园_品职助教 · 2022年03月21日

嗨,从没放弃的小努力你好:


万分抱歉,后台技术部门现在已经修改好了

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加油吧,让我们一起遇见更好的自己!

袁园_品职助教 · 2022年03月10日

嗨,爱思考的PZer你好:


谢谢提醒,已在追问技术部门中。

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加油吧,让我们一起遇见更好的自己!

袁园_品职助教 · 2022年02月14日

嗨,努力学习的PZer你好:


感谢指正,我们会在后台重新修改知识点分类的。

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就算太阳没有迎着我们而来,我们正在朝着它而去,加油!

大胃王瘦瘦 · 2022年03月09日

友情提醒,还没有改题目章节。

一只🐶哆啦 · 2022年03月21日

2022.3.21晚上这个题做的我一脸懵逼,我还没学那个中什么定理的,请尽快修改

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NO.PZ2017092702000107 问题如下 A population ha non-normstribution with meµ anvarianσ2. The sampling stribution of the sample mecomputefrom samples of large size from thpopulation will have: A.the same stribution the population stribution. B.its meapproximately equto the population mean. C.its varianapproximately equto the population variance. B is correct. Given a population scribeany probability stribution (normor nonnormal) with finite variance, the centrlimit theorem states ththe sampling stribution of the sample mewill approximately normal, with the meapproximately equto the population mean, when the sample size is large.给定具有有限方差的任何概率分布(正态或非正态)描述的总体,中心极限定理指出,当样本大小足够大的时候,样本均值为正态分布,其中样本均值等于总体均值。 No.PZ2017092702000107 (选择题)来源: 原版书A population ha non-normstribution with meµ anvarianσ2. The sampling stribution of the sample mecomputefrom samples of large size from thpopulation will have:您的回答正确答案是: BAthe same stribution the population stribution.B正确its meapproximately equto the population mean.Cits varianapproximately equto the population variance.请老师解答一下谢谢

2022-12-08 15:35 1 · 回答

NO.PZ2017092702000107 问题如下 A population ha non-normstribution with meµ anvarianσ2. The sampling stribution of the sample mecomputefrom samples of large size from thpopulation will have: A.the same stribution the population stribution. B.its meapproximately equto the population mean. C.its varianapproximately equto the population variance. B is correct. Given a population scribeany probability stribution (normor nonnormal) with finite variance, the centrlimit theorem states ththe sampling stribution of the sample mewill approximately normal, with the meapproximately equto the population mean, when the sample size is large.给定具有有限方差的任何概率分布(正态或非正态)描述的总体,中心极限定理指出,当样本大小足够大的时候,样本均值为正态分布,其中样本均值等于总体均值。 RT

2022-09-18 13:05 2 · 回答

请问老师A为什么是错的呢?不是说large就会都趋于正态分布吗?不就是same stribution吗?谢谢!

2019-11-21 15:16 2 · 回答

    提问请问老师A和C哪里错了?谢谢您

2018-10-26 17:31 1 · 回答