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沐沐的方盒 · 2022年02月02日

为什么explained variation是SSR?

NO.PZ2021071601000009

问题如下:

John, an analyst ran a simple regression explaining the variation in electricity consumption as a function of temperature. The total variation of the dependent variable was 132.08, and the explained variation was 60.38. She had 60 monthly observations.

Calculate the F-statistic to test the fit of the model.

选项:

A.49.68
B.48.84 C.

50.52

解释:

B is correct.

F=60.38/1(132.0860.38)/(602)=60.381.2362=48.84F = \frac{{60.38/1}}{{(132.08 - 60.38)/(60 - 2)}} = \frac{{60.38}}{{1.2362}} = 48.84

如题

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已采纳答案

星星_品职助教 · 2022年02月02日

同学你好,

这是SSR的直接定义,可参考下图讲义。

从公式里也可以看出,SSR的组成主体为 回归方程估计出来的值(Y cap)到Y的均值(Y bar)两者之间的距离的平方,这段距离就被认为是回归方程可以解释的真实数据值Yi偏离均值(Y bar)的部分。了解即可,不用掌握。

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NO.PZ2021071601000009 问题如下 John, analyst ra simple regression explaining the variation in electricity consumption a function of temperature. The totvariation of the pennt variable w132.08, anthe explainevariation w60.38. She h60 monthly observations. Calculate the F-statistic to test the fit of the mol. A.49.68 B.48.84 C.50.52 B is correct.F=60.38/1(132.08−60.38)/(60−2)=60.381.2362=48.84F = \frac{{60.38/1}}{{(132.08 - 60.38)/(60 - 2)}} = \frac{{60.38}}{{1.2362}} = 48.84F=(132.08−60.38)/(60−2)60.38/1​=1.236260.38​=48.84 请问explainevariation w60.38是SSR吗?我理解字面的意思是xy的变化的值为60.38. 所以我以为R2等于60.38

2022-12-25 05:01 1 · 回答

NO.PZ2021071601000009 问题如下 John, analyst ra simple regression explaining the variation in electricity consumption a function of temperature. The totvariation of the pennt variable w132.08, anthe explainevariation w60.38. She h60 monthly observations. Calculate the F-statistic to test the fit of the mol. A.49.68 B.48.84 C.50.52 B is correct.F=60.38/1(132.08−60.38)/(60−2)=60.381.2362=48.84F = \frac{{60.38/1}}{{(132.08 - 60.38)/(60 - 2)}} = \frac{{60.38}}{{1.2362}} = 48.84F=(132.08−60.38)/(60−2)60.38/1​=1.236260.38​=48.84

2022-09-14 23:08 1 · 回答

NO.PZ2021071601000009问题如下 John, analyst ra simple regression explaining the variation in electricity consumption a function of temperature. The totvariation of the pennt variable w132.08, anthe explainevariation w60.38. She h60 monthly observations. Calculate the F-statistic to test the fit of the mol. A.49.68B.48.84C.50.52 B is correct.F=60.38/1(132.08−60.38)/(60−2)=60.381.2362=48.84F = \frac{{60.38/1}}{{(132.08 - 60.38)/(60 - 2)}} = \frac{{60.38}}{{1.2362}} = 48.84F=(132.08−60.38)/(60−2)60.38/1​=1.236260.38​=48.84 老师 可否再讲一下F检验的使用场景和意义?以及它跟Z检验 T检验的区别?还是不太理解

2022-07-16 20:43 1 · 回答

NO.PZ2021071601000009 这道题用的是哪个公式啊?

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