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风归去 · 2021年08月22日

AE的计算

NO.PZ2020033002000004

问题如下:

A bank granted Client A a total credit facility of $500,000, of which 70% is currently outstanding. The client's probability of default for the following year is estimated to be 2%, the loss given default is 50%, and the standard deviation of loss given default is 30%. The undrawn portion at the time of default assumes a 50% withdrawal. What is the bank's best estimate of expected and unexpected losses (standard deviation) ?

选项:

A.

EL = $3500, UL = $55,229

B.

EL = $3500, UL = $28,649

C.

EL = $4250, UL = $67,064

D.

EL = $4250, UL = $34,788

解释:

D is correct.

考点:Risk Contribution

解析:

AE=70%x$500,000+50%*30%*$500,000=$425,000

EL=425,000*2%*50%=4250

UL的公式如下:

UL=AEp×σLGD2+p×(1p)×LGD2UL=AE\ast\sqrt{p\times\sigma_{LGD}^2+p\times{(1-p)}\times{LGD}^2}

代入公式,有

UL=34,788

No.PZ2020033002000004 

该问题中敞口AE的计算公式有些不太理解,能具体说明一下吗?

2 个答案
已采纳答案

李坏_品职助教 · 2021年08月24日

嗨,爱思考的PZer你好:


这句话意思是:还没借出去的30%那部分,要记入AE的是50%的withdrawal。(withdrawal是被借款人取走的,就是bank可能损失掉的部分)


如果改成30%的withdrawal,那么就是要按照30%计入AE了。

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就算太阳没有迎着我们而来,我们正在朝着它而去,加油!

李坏_品职助教 · 2021年08月22日

嗨,爱思考的PZer你好:


AE是这样的计算的,首先是银行已经借出去的(outstanding)的部分70% * 500000。

然后没借出去的部分有30%, 这些没借出去的部分的敞口是按照LGD的50%来计算,也就是30% * 50% * 500000。


然后二者加起来即可。

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虽然现在很辛苦,但努力过的感觉真的很好,加油!

风归去 · 2021年08月24日

The undrawn portion at the time of default assumes a 50% withdrawal中 50% withdrawal是指损失还是未损失的敞口,比如说条件改成The undrawn portion at the time of default assumes a 30% withdrawal,那么没借出去的敞口是按照30%计提还是70%加入敞口?

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NO.PZ2020033002000004 问题如下 A bank granteClient A a totcret facility of $500,000, of whi70% is currently outstanng. The client's probability of fault for the following yeis estimateto 2%, the loss given fault is 50%, anthe stanrviation of loss given fault is 30%. The unawn portion the time of fault assumes a 50% withawal. Whis the bank's best estimate of expecteanunexpectelosses (stanrviation) ? EL = $3500, UL = $55,229 B.EL = $3500, UL = $28,649 C.EL = $4250, UL = $67,064 EL = $4250, UL = $34,788 is correct.考点Risk Contribution解析AE=70%x$500,000+50%*30%*$500,000=$425,000EL=425,000*2%*50%=4250UL的公式如下UL=AE∗p×σLG+p×(1−p)×LGUL=AE\ast\sqrt{p\times\sigma_{LG^2+p\times{(1-p)}\times{LG^2}UL=AE∗p×σLG​+p×(1−p)×LG​代入公式,有UL=34,788 AE=70%x$500,000+50%*30%*$500,000=$425,000解析里这条公式为什么要两部分相加?我理解不是只计算后面那部分就可以了吗?

2024-09-07 15:58 2 · 回答

NO.PZ2020033002000004 问题如下 A bank granteClient A a totcret facility of $500,000, of whi70% is currently outstanng. The client's probability of fault for the following yeis estimateto 2%, the loss given fault is 50%, anthe stanrviation of loss given fault is 30%. The unawn portion the time of fault assumes a 50% withawal. Whis the bank's best estimate of expecteanunexpectelosses (stanrviation) ? EL = $3500, UL = $55,229 B.EL = $3500, UL = $28,649 C.EL = $4250, UL = $67,064 EL = $4250, UL = $34,788 is correct.考点Risk Contribution解析AE=70%x$500,000+50%*30%*$500,000=$425,000EL=425,000*2%*50%=4250UL的公式如下UL=AE∗p×σLG+p×(1−p)×LGUL=AE\ast\sqrt{p\times\sigma_{LG^2+p\times{(1-p)}\times{LG^2}UL=AE∗p×σLG​+p×(1−p)×LG​代入公式,有UL=34,788

2023-03-16 15:55 1 · 回答

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2021-10-20 22:49 1 · 回答