开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

Trees · 2021年01月17日

问一道题:NO.PZ201702190300000306 第6小题 [ CFA II ]

* 问题详情,请 查看题干

问题如下:

6.The value of the American-style put option on Beta Company shares is closest to:

选项:

A.

4.53.

B.

5.15.

C.

9.32.

解释:

B is correct.

Using the expectations approach, the risk-neutral probability of an up move is

π= [FV(1) - d]/(u - d) = (1.03 - 0.800)/(1.300 - 0.800) = 0.46.

An American-style put can be exercised early. At Time Step 1, for the up move, p+ is 0.2517 and the put is out of the money and should not be exercised early (X < S, 40 < 49.4). However, at Time Step 1, p- is 8.4350 and the put is in the money by 9.60 (X - S = 40 - 30.40). So, the put is exercised early, and the value of early exercise (9.60) replaces the value of not exercising early (8.4350) in the binomial tree. The value of the put at Time Step 0 is now

p = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(9.60)] = 5.1454.

Following is a supplementary note regarding Exhibit 1.

The values in Exhibit 1 are calculated as follows.

At Time Step 2:

p++ = Max(0,X - u2S) = Max[0,40 - 1.3002(38)] = Max(0,40 - 64.22) = 0.

p-+ = Max(0,X - udS) = Max[0,40 - 1.300(0.800)(38)] = Max(0,40 - 39.52) = 0.48.

p- - = Max(0,X - d2S) = Max[0,40 - 0.8002(38)] = Max(0,40 - 24.32)= 15.68.

At Time Step 1:

p+ = PV[πp++ + (1 - π)p-+] = [1/(1.03)][0.46(0) + 0.54(0.48)] = 0.2517.

p- = PV[πp-+ + (1 - π)p- -] = [1/(1.03)][0.46(0.48) + 0.54(15.68)]=8.4350.

At Time Step 0:

p = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(8.4350)] = 4.5346.

为什么结果不是p= [1/(1.03)][0.46(0)+ 0.54(9.60)] = 5.03呢,因为在p1+时,49.4>40,p1+=0
1 个答案

WallE_品职答疑助手 · 2021年01月18日

同学您好

因为这是2期的美式期权,

在T=1时刻,up move是OTM,但是将T=2时刻的UP MOVE结点的结果折现到T=1时刻,put value=0.2517, 它是大于0的。所以是答案的解法而非您所说的0.

对于美式来说,我们都会取一个最好的结果,当股票价格上升的时候,我们不会选择提前执行,而会等到T=2时刻,这样更有利。

  • 1

    回答
  • 0

    关注
  • 879

    浏览
相关问题

NO.PZ201702190300000306 问题如下 The value of the American-style put option on Beta Company shares is closest to: A.4.53. B.5.15. C.9.32. B is correct.Using the expectations approach, the risk-neutrprobability of up move isπ= [FV(1) - /(u - = (1.03 - 0.800)/(1.300 - 0.800) = 0.46.American-style put cexerciseearly. Time Step 1, for the up move, p+ is 0.2517 anthe put is out of the money anshoulnot exerciseearly (X S, 40 49.4). However, Time Step 1, p- is 8.4350 anthe put is in the money 9.60 (X - S = 40 - 30.40). So, the put is exerciseearly, anthe value of early exercise (9.60) replaces the value of not exercising early (8.4350) in the binomitree. The value of the put Time Step 0 is nowp = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(8.4350)] = 4.54.Following is a supplementary note regarng Exhibit 1.The values in Exhibit 1 are calculatefollows.Time Step 2:p++ = Max(0,X - u2S) = Max[0,40 - 1.3002(38)] = Max(0,40 - 64.22) = 0. p-+ = Max(0,X - u) = Max[0,40 - 1.300(0.800)(38)] = Max(0,40 - 39.52) = 0.48.p- - = Max(0,X - S) = Max[0,40 - 0.8002(38)] = Max(0,40 - 24.32)= 15.68.Time Step 1:p+ = PV[πp++ + (1 - π)p-+] = [1/(1.03)][0.46(0) + 0.54(0.48)] = 0.2517. p- = PV[πp-+ + (1 - π)p- -] = [1/(1.03)][0.46(0.48) + 0.54(15.68)]=8.4350.Time Step 0:p = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(9.6)] = 5.1454.中文解析本题考察的是计算美式看跌期权的价值,需要注意的是在t=1的节点,需要判断是否有必要提前行权。在本题中,在p- 的确定时,就需要考虑这个问题,如果在t=1时刻立即行权,p- 等于9.6,如果在t=2时刻行权,折现后求得的p- 为8.4350.两者取大,因此应该在t=1时刻行权,得到p- 等于9.6.然后再根据p- =9.6,p+ =0.2517折现到0时刻得到p0. P+和P-为什么不统一呢,就是折现就都折现,不折现就都不折现,怎么有的折现有的是直接算的?

2023-07-27 16:40 2 · 回答

NO.PZ201702190300000306 问题如下 The value of the American-style put option on Beta Company shares is closest to: A.4.53. B.5.15. C.9.32. B is correct.Using the expectations approach, the risk-neutrprobability of up move isπ= [FV(1) - /(u - = (1.03 - 0.800)/(1.300 - 0.800) = 0.46.American-style put cexerciseearly. Time Step 1, for the up move, p+ is 0.2517 anthe put is out of the money anshoulnot exerciseearly (X S, 40 49.4). However, Time Step 1, p- is 8.4350 anthe put is in the money 9.60 (X - S = 40 - 30.40). So, the put is exerciseearly, anthe value of early exercise (9.60) replaces the value of not exercising early (8.4350) in the binomitree. The value of the put Time Step 0 is nowp = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(8.4350)] = 4.54.Following is a supplementary note regarng Exhibit 1.The values in Exhibit 1 are calculatefollows.Time Step 2:p++ = Max(0,X - u2S) = Max[0,40 - 1.3002(38)] = Max(0,40 - 64.22) = 0. p-+ = Max(0,X - u) = Max[0,40 - 1.300(0.800)(38)] = Max(0,40 - 39.52) = 0.48.p- - = Max(0,X - S) = Max[0,40 - 0.8002(38)] = Max(0,40 - 24.32)= 15.68.Time Step 1:p+ = PV[πp++ + (1 - π)p-+] = [1/(1.03)][0.46(0) + 0.54(0.48)] = 0.2517. p- = PV[πp-+ + (1 - π)p- -] = [1/(1.03)][0.46(0.48) + 0.54(15.68)]=8.4350.Time Step 0:p = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(9.6)] = 5.1454.中文解析本题考察的是计算美式看跌期权的价值,需要注意的是在t=1的节点,需要判断是否有必要提前行权。在本题中,在p- 的确定时,就需要考虑这个问题,如果在t=1时刻立即行权,p- 等于9.6,如果在t=2时刻行权,折现后求得的p- 为8.4350.两者取大,因此应该在t=1时刻行权,得到p- 等于9.6.然后再根据p- =9.6,p+ =0.2517折现到0时刻得到p0. 如题

2022-08-09 15:05 2 · 回答

NO.PZ201702190300000306 上一小题是求欧式看涨期权的价值,就是直接得到time 2的C++,C+-和C--,然后就直接用rf往前折现两年变得出价值 这题为什么是先折现到time 1,然后再这些到0时刻?

2021-09-29 23:19 1 · 回答

5.15. 9.32. B is correct. Using the expectations approach, the risk-neutrprobability of up move is π= [FV(1) - /(u - = (1.03 - 0.800)/(1.300 - 0.800) = 0.46. American-style put cexerciseearly. Time Step 1, for the up move, p+ is 0.2517 anthe put is out of the money anshoulnot exerciseearly (X < S, 40 < 49.4). However, Time Step 1, p- is 8.4350 anthe put is in the money 9.60 (X - S = 40 - 30.40). So, the put is exerciseearly, anthe value of early exercise (9.60) replaces the value of not exercising early (8.4350) in the binomitree. The value of the put Time Step 0 is now p = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(9.60)] = 5.1454. Following is a supplementary note regarng Exhibit 1. The values in Exhibit 1 are calculatefollows. Time Step 2: p++ = Max(0,X - u2S) = Max[0,40 - 1.3002(38)] = Max(0,40 - 64.22) = 0. p-+ = Max(0,X - u) = Max[0,40 - 1.300(0.800)(38)] = Max(0,40 - 39.52) = 0.48. p- - = Max(0,X - S) = Max[0,40 - 0.8002(38)] = Max(0,40 - 24.32)= 15.68. Time Step 1: p+ = PV[πp++ + (1 - π)p-+] = [1/(1.03)][0.46(0) + 0.54(0.48)] = 0.2517. p- = PV[πp-+ + (1 - π)p- -] = [1/(1.03)][0.46(0.48) + 0.54(15.68)]=8.4350. Time Step 0: p = PV[πp+ + (1 - π)p-] = [1/(1.03)][0.46(0.2517) + 0.54(8.4350)] = 4.5346.请问既然已经确定在1时刻行权了,为什么在计算put value时还要加上0。2517呢,这个地方不太明白

2020-08-08 23:19 1 · 回答