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hillock1122 · 2021年01月17日

问一道题:NO.PZ2018122701000073 [ FRM II ]

问题如下:

For a 2-year zero-coupon bond, the 1-year rate is expected to remain at 5% for the first year. For the second year, it is foretasted the that 1-year spot rate will be either 7% or 3% at equal probability of 50%. If you are asked to reflect the convexity effect for this 2-year bond by Jensen’s inequality formula, which of the following inequalities is the best answer?

选项:

A.

$0.90736 > $0.90703.

B.

$0.90703 > $0.90000.

C.

$0.95238 > $0.90736.

D.

$0.95273 > $0.95238

解释:

A is correct.

考点:Jensen's inequality formula

解析:

不等式左边

E(11+r)=0.5×11.07+0.5×11.03=0.95273E(\frac1{1+r})=0.5\times\frac1{1.07}+0.5\times\frac1{1.03}=0.95273

0.95273/1.05 = 0.90736

不等式右边

$10.5×1.07+0.5×1.03=$11.05=0.95238\frac{\$1}{0.5\times1.07+0.5\times1.03}=\frac{\$1}{1.05}=0.95238

0.95238/1.05 = 0.90703

为什么都需要再除以一个1.05呢?

1 个答案
已采纳答案

品职答疑小助手雍 · 2021年01月18日

嗨,努力学习的PZer你好:


最终求的是当前的PV,前面阶段求的是1年后节点的价值,还要通过近一年的收益率折现。


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就算太阳没有迎着我们而来,我们正在朝着它而去,加油!


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NO.PZ2018122701000073问题如下 For a 2-yezero-coupon bon the 1-yerate is expecteto remain 5% for the first year. For the seconyear, it is foretastethe th1-yespot rate will either 7% or 3% equprobability of 50%. If you are asketo reflethe convexity effefor this 2-yebonJensen’s inequality formulwhiof the following inequalities is the best answer? A.$0.90736 $0.90703.B.$0.90703 $0.90000.C.$0.95238 $0.90736.$0.95273 $0.95238 A is correct.考点Jensen's inequality formula解析不等式左边E(11+r)=0.5×11.07+0.5×11.03=0.95273E(\frac1{1+r})=0.5\times\frac1{1.07}+0.5\times\frac1{1.03}=0.95273E(1+r1​)=0.5×1.071​+0.5×1.031​=0.952730.95273/1.05 = 0.90736 不等式右边$10.5×1.07+0.5×1.03=$11.05=0.95238\frac{\$1}{0.5\times1.07+0.5\times1.03}=\frac{\$1}{1.05}=0.952380.5×1.07+0.5×1.03$1​=1.05$1​=0.952380.95238/1.05 = 0.90703 如题,怎么确定要不要再除以1.05%折现回0时刻呢?

2023-02-06 10:22 2 · 回答

NO.PZ2018122701000073 问题如下 For a 2-yezero-coupon bon the 1-yerate is expecteto remain 5% for the first year. For the seconyear, it is foretastethe th1-yespot rate will either 7% or 3% equprobability of 50%. If you are asketo reflethe convexity effefor this 2-yebonJensen’s inequality formulwhiof the following inequalities is the best answer? A.$0.90736 $0.90703. B.$0.90703 $0.90000. C.$0.95238 $0.90736. $0.95273 $0.95238 A is correct.考点Jensen's inequality formula解析不等式左边E(11+r)=0.5×11.07+0.5×11.03=0.95273E(\frac1{1+r})=0.5\times\frac1{1.07}+0.5\times\frac1{1.03}=0.95273E(1+r1​)=0.5×1.071​+0.5×1.031​=0.952730.95273/1.05 = 0.90736 不等式右边$10.5×1.07+0.5×1.03=$11.05=0.95238\frac{\$1}{0.5\times1.07+0.5\times1.03}=\frac{\$1}{1.05}=0.952380.5×1.07+0.5×1.03$1​=1.05$1​=0.952380.95238/1.05 = 0.90703 右边等式应该是 1/Er=1/E(1+r)但是 这1/E(1+r)应该怎么理解啊 李老师讲的时候我就没听懂 就是

2023-01-17 22:51 1 · 回答

NO.PZ2018122701000073 $0.90703 > $0.90000. $0.95238 > $0.90736. $0.95273 > $0.95238 A is correct. 考点Jensen's inequality formula 解析 不等式左边 E(11+r)=0.5×11.07+0.5×11.03=0.95273E(\frac1{1+r})=0.5\times\frac1{1.07}+0.5\times\frac1{1.03}=0.95273E(1+r1​)=0.5×1.071​+0.5×1.031​=0.95273 0.95273/1.05 = 0.90736 不等式右边 $10.5×1.07+0.5×1.03=$11.05=0.95238\frac{\$1}{0.5\times1.07+0.5\times1.03}=\frac{\$1}{1.05}=0.952380.5×1.07+0.5×1.03$1​=1.05$1​=0.95238 0.95238/1.05 = 0.90703 右侧 3%与7%平均是5% ,可否直接用5%作为第二年利率折现,这样更为简便 

2022-01-12 12:29 1 · 回答