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Feeling · 2020年10月31日

问一道题:NO.PZ201512181000007102

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问题如下:

The number of Flusk’s VaR breaches most likely resulted from:

选项:

A.

using a standard normal distribution in the VaR model.

B.

using a 95% confidence interval instead of a 99% confidence interval.

C.

lower market volatility during the last year compared with the lookback period.

解释:

C is correct. Flusk experienced zero daily VaR breaches over the last year yet incurred a substantial loss. A limitation of VaR is its vulnerability to different volatility regimes. A portfolio might remain under its VaR limit every day but lose an amount approaching this limit each day. If market volatility during the last year is lower than in the lookback period, the portfolio could accumulate a substantial loss without technically breaching the VaR constraint.

A is incorrect because VaR was calculated using historical simulation, so the distribution used was based on actual historical changes in the key risk factors experienced during the lookback period. Thus, the distribution is not characterized using estimates of the mean return, the standard deviation, or the correlations among the risk factors in the portfolio. In contrast, the parametric method of estimating VaR generally assumes that the distribution of returns for the risk factors is normal.

B is incorrect because a specification with a higher confidence level will produce a higher VaR. If a 99% confidence interval was used to calculate historical VaR, the VaR would be larger (larger expected minimum loss). During the last year, none of Flusk’s losses were substantial enough to breach the 5% VaR number (95% confidence interval); therefore, if McKee used a 1% VaR (99% confidence interval), the number of VaR breaches would not change.

为什么99%的confidence level会导致VaR更大呢?

99%的Z值更大,expected return减去更大Z值*标准差,不是会让VaR更小吗?

1 个答案
已采纳答案

星星_品职助教 · 2020年11月02日

同学你好,

VaR是分布里左尾的区域,也就是loss的概念。减去更大z值后,会使得对应的分位点更往左靠,对应的是(最小)损失更大。