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mango · 2017年11月08日

问一道题:NO.PZ2016082406000005 [ FRM II ]

问题如下图:
选项:
A.
B.
C.
D.
解释:
选项三不是特别理解,谢谢!
1 个答案

Shimin_CPA税法主讲、CFA教研 · 2017年11月10日

我个人觉得EL和UL没法比较谁增的快,因为一个是average,一个是standard deviation。尝试用求导的方法比大小,无解。记一下结论吧

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fine unexpecteloss (UL) the stanrviation of losses anexpecteloss (EL) the average loss. Further fine LGloss given fault, anE the expectefault frequency. Whiof the following statements hols) true? I.     EL increases linearly with increasing E. II.   EL is often higher thUL. III. With increasing E, UL increases a mufaster rate thEL. IV. The lower the LG the higher the percentage loss for both the EL anUL. I only I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses. 你好请问III应该怎么理解,为什么一单位P上升UL比EL提升多

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