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SkipperLin · 2020年02月22日

问一道题:NO.PZ2016062402000022

问题如下:

A portfolio manager is interested in the systematic risk of a stock portfolio, so he estimates the linear regression: RPtRF=αP+βP[RMtRF]+εPtR_{Pt}-R_F=\alpha_P+\beta_P{\lbrack R_{Mt}-R_F\rbrack}+\varepsilon_{Pt},where RPtR_{Pt} is the return of the portfolio at time t, RMtR_{Mt} is the return of the market portfolio at time t, and RFR_F is the risk-free rate, which is constant over time. Suppose that α = 0.008, β = 0.977, σ(RP)\sigma{(R_P)} = 0.167, and σ(RM)\sigma{(R_M)} = 0.156.

What is the approximate coefficient of determination in this regression?

选项:

A.

0.913

B.

0.834

C.

0.977

D.

0.955

解释:

the R-squared is given by β2σM2σP2=0.9772×0.15620.1672=0.83\frac{\beta^2\sigma_M^2}{\sigma_P^2}=0.977^2\times\frac{0.156^2}{0.167^2}=0.83

请问相关系数=b*X的标准差/Y的标准差这个是怎么来的呢

1 个答案
已采纳答案

品职答疑小助手雍 · 2020年02月22日

同学你好,coefficient of determination即决定系数,就是R方。一元回归中,R方等于rho的平方。

β=ρ*σp/σm,变形后ρ=β*σm/σp,等号两边同取平方即可。

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NO.PZ2016062402000022问题如下 A portfolio manager is interestein the systematic risk of a stoportfolio, so he estimates the lineregression: RPt−RF=αP+βP[RMt−RF]+εPtR_{Pt}-R_F=\alpha_P+\beta_P{\lbraR_{Mt}-R_F\rbrack}+\varepsilon_{Pt}RPt​−RF​=αP​+βP​[RMt​−RF​]+εPt​,where RPtR_{Pt}RPt​ is the return of the portfolio time t, RMtR_{Mt}RMt​ is the return of the market portfolio time t, anRFR_FRF​ is the risk-free rate, whiis constant over time. Suppose thα = 0.008, β = 0.977, σ(RP)\sigma{(R_P)}σ(RP​) = 0.167, anσ(RM)\sigma{(R_M)}σ(RM​) = 0.156.Whis the approximate coefficient of termination in this regression? 0.913 0.834 0.977 0.955 the R-squareis given β2σM2σP2=0.9772×0.15620.1672=0.83\frac{\beta^2\sigma_M^2}{\sigma_P^2}=0.977^2\times\frac{0.156^2}{0.167^2}=0.83σP2​β2σM2​​=0.9772×0.16720.1562​=0.83 决策系数怎么就是拟合优度了?

2023-03-21 11:10 1 · 回答

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2022-11-17 15:57 1 · 回答

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2022-03-29 07:58 1 · 回答

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2022-01-16 13:42 1 · 回答

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