开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

Infinite · 2020年02月03日

问一道题:NO.PZ2020010301000009

问题如下:

Credit card companies rapidly assess transactions for fraud. In each day, a large card issuer assesses 10,000,000 transactions. Of these, 0.001% are fraudulent. If their algorithm identifies 90% of all fraudulent transactions but also 0.0001% of legitimate transactions, what is the probability that a transaction is fraudulent if it has been flagged?

选项:

A.

90%

B.

80%

C.

95%

D.

10%

解释:

We are interested in Pr(Fraud|Flag). This value is Pr(Fraud∪Flag)/Pr(Flag). The probability that a transaction is flagged is

.001% * 90% + 99.999% * 0.0001% = .000999%.

The Pr(Fraud∪Flag) = .001% * 90% = .0009.

Combining these values,

.0009 /.000999 = 90%.

This indicates that 10% of the flagged transactions are not actually fraudulent.

Pr(Fraud∪Flag)/Pr(Flag),我没明白这个公式 为什么是p(fraud u flag)?

1 个答案

品职答疑小助手雍 · 2020年02月07日

同学你好,这里是贝叶斯公式的变形,我下面那个截图的等式两边同除以P(B)就跟这题的公式一样了。