问题如下图：
选项：
A. 
B. 
C. 
解释：
（1.2—0.4）/（1.5-0.4）不对吗？
NO.PZ201512020300000606 问题如下 Baseon Exhibit 1, for the firm with I#3, Steele shoulcompute the scalevalue for the “Interest Expense” variable as: A.0.008 B.0.083 C.0.250 B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation(Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin) :The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateXi (normalize =0.083 我的计算理解是将4家公司的利息成本数据进行计算，请老师指正错误分子1.2减0.4；分母1.5减0.4，
NO.PZ201512020300000606 问题如下 Baseon Exhibit 1, for the firm with I#3, Steele shoulcompute the scalevalue for the “Interest Expense” variable as: A.0.008 B.0.083 C.0.250 B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation(Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin) :The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateXi (normalize =0.083 我理解这个公式，不应该是1.1-0.2】/12.2-0.2，不是这样么
NO.PZ201512020300000606 老师，这里也可以算stanrzation，1.2-0.2/4，为什么要用normailization？
NO.PZ201512020300000606 老师，怎么就通过此题问题联系到normalization？
老师问下 这道题不是（1.2-0.4）/（12.2-0.2）=0.8吗 0.833怎么算的呀
