问题如下图：
请问为什么算p（flag）的时候legitimate部分时乘以的是99.999%而不是（1-0.001%）？谢谢！
选项：
A. 
B. 
C. 
D. 
解释：
NO.PZ2020010301000009 问题如下 Cret carcompanies rapiy assess transactions for frau In eay, a large carissuer assesses 10,000,000 transactions. Of these, 0.001% are fraulent. If their algorithm intifies 90% of all fraulent transactions but also 0.0001% of legitimate transactions, whis the probability tha transaction is fraulent if it hbeen flagge A.90% B.80% C.95% 10% We are interestein Pr(FrauFlag). This value is Pr(Frau\cap∩Flag)/Pr(Flag). The probability tha transaction is flaggeis.001% * 90% + 99.999% * 0.0001% = .000999%.The Pr(Frau\cap∩Flag) = .001% * 90% = .0009.Combining these values,.0009 /.000999 = 90%.This incates th10% of the flaggetransactions are not actually fraulent. 画图法怎么画这道题，求解
老师能一下这道题的意思吗
请问这个数学运算怎么做的？我总是算不对
请问这题的答案解析是不是写错了，按照贝叶斯公式变形后，frauflag在分子应该为交集而不是并集吧？
请问什么叫flagged
