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我们 · 2019年10月29日

问一道题:NO.PZ2019070101000017

问题如下图:

    

选项:

A.

B.

C.

D.

解释:

你好,这个题答案是不是有问题?我算的是0.66?我看解析好像也不大对,还是我算的有问题呢?因为我算了3遍都是0.66



1 个答案

品职答疑小助手雍 · 2019年10月29日

同学你好哦,你说的没错,这里put第2年最后一个节点的value应该是3.87,而不是0.87。算下来是0.66,谢谢指出。

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NO.PZ2019070101000017 问题如下 Suses the two-periobinomimol to estimate the value of a two-ye European- style put option on Bet Company’s common shares. The inputs are follows.The current stopriis 96, anthe put option exercise priis 70.The up factor (u) is 1.20, anthe wn factor ( is 0.83.The risk-free rate of return is 4%. The value of the option is close to? A.$0.66. B.$1.97. C.$2.18. $0.98. A is correct.考点A Two-Step BinomiMol解析u=1.2,1/u=1/1.2=0.83p=(e0.04-0.83)/(1.2-0.83)=0.57$ 0=e-0.04(0*0.57+0*0.43)$ 1.60= e-0.04(0*0.57+3.87*0.43)$ 0.66= e-0.04(0*0.57+1.60*0.43) 这里不太明白

2024-04-08 20:40 1 · 回答

NO.PZ2019070101000017问题如下Suses the two-periobinomimol to estimate the value of a two-ye European- style put option on Bet Company’s common shares. The inputs are follows.The current stopriis 96, anthe put option exercise priis 70.The up factor (u) is 1.20, anthe wn factor ( is 0.83.The risk-free rate of return is 4%. The value of the option is close to? A.$0.66.B.$1.97.C.$2.18.$0.98.A is correct.考点A Two-Step BinomiMol解析u=1.2,1/u=1/1.2=0.83p=(e0.04-0.83)/(1.2-0.83)=0.57$ 0=e-0.04(0*0.57+0*0.43)$ 1.60= e-0.04(0*0.57+3.87*0.43)$ 0.66= e-0.04(0*0.57+1.60*0.43)这不是欧式期权吗?怎么答案按美式期权计算的

2023-03-01 17:33 2 · 回答

NO.PZ2019070101000017问题如下Suses the two-periobinomimol to estimate the value of a two-ye European- style put option on Bet Company’s common shares. The inputs are follows.The current stopriis 96, anthe put option exercise priis 70.The up factor (u) is 1.20, anthe wn factor ( is 0.83.The risk-free rate of return is 4%. The value of the option is close to? A.$0.66.B.$1.97.C.$2.18.$0.98.A is correct.考点A Two-Step BinomiMol解析u=1.2,1/u=1/1.2=0.83p=(e0.04-0.83)/(1.2-0.83)=0.57$ 0=e-0.04(0*0.57+0*0.43)$ 1.60= e-0.04(0*0.57+3.87*0.43)$ 0.66= e-0.04(0*0.57+1.60*0.43)请问解析中的1.6是怎么来的ya

2022-10-16 16:45 2 · 回答

     老师你好,这里的C2--应该是3.87,而不是0.83吧

2019-10-25 11:22 1 · 回答