问一道题：NO.PZ2015120604000106 [ CFA I ]-有问必答-品职教育专注CFA ESG FRM CPA 考研等财经培训课程

NO.PZ2015120604000106 问题如下 For a normally stributeranm variable, the probability thranm varible is greater ththree stanrviations excess the meis: A.0.0013. B.0.0228. C.0.9987. A is correct.1 - F(3) = 1 - 0.9987 = 0.0013. 如标题

2022-11-03 19:02 1 · 回答

NO.PZ2015120604000106问题如下For a normally stributeranm variable, the probability thranm varible is greater ththree stanrviations excess the meis:A.0.0013.B.0.0228.C.0.9987.A is correct.1 - F(3) = 1 - 0.9987 = 0.0013.这里Z大于等于3，3是怎么算出来的？

2022-09-02 15:49 1 · 回答

NO.PZ2015120604000106问题如下For a normally stributeranm variable, the probability thranm varible is greater ththree stanrviations excess the meis:A.0.0013.B.0.0228.C.0.9987.A is correct.1 - F(3) = 1 - 0.9987 = 0.0013.为什么就等于是求X-μ≥3σ的概率？X-μ是什么

2022-08-10 20:38 1 · 回答

NO.PZ2015120604000106 问题如下 For a normally stributeranm variable, the probability thranm varible is greater ththree stanrviations excess the meis: A.0.0013. B.0.0228. C.0.9987. A is correct.1 - F(3) = 1 - 0.9987 = 0.0013. '题目问服从正态分布的随机变量落在超过均值3个标准差的部分的概率为多少。也就是要求的就是X-μ≥3σ的概率\",老师为什么题干可以解读出要求的是X-μ≥3σ的概率，能一下这个不等式是怎么得出来的吗，运用的是哪个知识点？

2022-05-03 18:57 4 · 回答

NO.PZ2015120604000106 0.0228. 0.9987. A is correct. 1 - F(3) = 1 - 0.9987 = 0.0013. 根据正态分布标准化的公式（X-μ）/σ进行转化，相当于求P(Z≥3)。———解析中这句话没有理解

2022-02-27 12:52 3 · 回答

问一道题：NO.PZ2015120604000106 [ CFA I ]

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