开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

ciaoyy · 2019年07月13日

问一道题:NO.PZ2016082406000005

问题如下图:

    

选项:

A.

B.

C.

D.

解释:


EL=PD*LGD*EAD,为什么说EL、PD是线性关系呢?

1 个答案
已采纳答案

品职答疑小助手雍 · 2019年07月14日

同学你好,单就这个EL的公式来说,不去管LGD和EAD,只讨论EL和PD的关系,那么EL和PD就是线性关系了,随着PD增加,EL也线性增加。

  • 1

    回答
  • 0

    关注
  • 337

    浏览
相关问题

fine unexpecteloss (UL) the stanrviation of losses anexpecteloss (EL) the average loss. Further fine LGloss given fault, anE the expectefault frequency. Whiof the following statements hols) true? I.     EL increases linearly with increasing E. II.   EL is often higher thUL. III. With increasing E, UL increases a mufaster rate thEL. IV. The lower the LG the higher the percentage loss for both the EL anUL. I only I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses. 你好请问III应该怎么理解,为什么一单位P上升UL比EL提升多

2020-10-23 12:51 1 · 回答

fine unexpecteloss (UL) the stanrviation of losses anexpecteloss (EL) the average loss. Further fine LGloss given fault, anE the expectefault frequency. Whiof the following statements hols) true? I.     EL increases linearly with increasing E. II.   EL is often higher thUL. III. With increasing E, UL increases a mufaster rate thEL. IV. The lower the LG the higher the percentage loss for both the EL anUL. I only I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses. 请问III如何理解

2020-08-26 13:27 1 · 回答

fine unexpecteloss (UL) the stanrviation of losses anexpecteloss (EL) the average loss. Further fine LGloss given fault, anE the expectefault frequency. Whiof the following statements hols) true? I.     EL increases linearly with increasing E. II.   EL is often higher thUL. III. With increasing E, UL increases a mufaster rate thEL. IV. The lower the LG the higher the percentage loss for both the EL anUL. I only I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses. 老师4 错哪里了

2020-08-16 21:59 1 · 回答

I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses.老师,这个E指的是什么?

2020-05-22 17:19 2 · 回答

fine unexpecteloss (UL) the stanrviation of losses anexpecteloss (EL) the average loss. Further fine LGloss given fault, anE the expectefault frequency. Whiof the following statements hols) true? I.     EL increases linearly with increasing E. II.   EL is often higher thUL. III. With increasing E, UL increases a mufaster rate thEL. IV. The lower the LG the higher the percentage loss for both the EL anUL. I only I anII I anIII II anIV ANSWER: C Equation: E(CL)=E(n)E(LG=NpE(LGE{(CL)}=E{(n)}E{(LG}=NpE{(LG}E(CL)=E(n)E(LG=NpE(LGshows thEL increases linearly with p, so answer I. is correct. Answer II. is not correct, certainly for concentrateportfolios. Equation: σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2\sigma{(CL)}=\sqrt{p\times\sigma^2{(LG}+p\times{(1-p)}\times{\lbraE{(LG}\rbrack}^2}σ(CL)=p×σ2(LG+p×(1−p)×[E(LG]2 ​shows thUL increases faster thEL linearly with p, so answer III. is correct. Finally, Answer II. is incorrect, higher (not lower) LGwoulleto higher cret losses. E(CL)=E(n)E(LG=NpE(LG 老师,这个式子没有看懂可以一下吗?谢谢

2020-03-22 16:50 1 · 回答