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木木__ · 2019年02月05日

问一道题:NO.PZ201709270100000305 第5小题

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问题如下图:

    

选项:

A.

B.

C.

解释:

老师您好,根据先前同学提问的回答,大与不大怎么去看呢 是否以0.7作为衡量标准,但如果是的话 本来B1 B2也没有达到0.7,所以这题应该怎么考虑会比较好


1 个答案

菲菲_品职助教 · 2019年02月11日

同学你好,这个相关系数大与不大是相对而言的。相对于已经存在的自变量,可以判断新增加的这个自变量跟因变量的相关系数一定是不大的,即对因变量的解释力度不大,那么adjusted R²是减小的而不是增加的。

saimeiei · 2019年05月07日

请问怎么判断新加入的自变量对因变量的解释力度大还是不大

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NO.PZ201709270100000305 问题如下 BrVarn, a junior analyst actively managemutufun is responsible for researon a subset of the 500 large-cequities the funfollows. Recently, the funhbeen paying close attention to management turnover anto publicly available environmental, social, angovernan(ESG) ratings. Varn is given the task of investigating whether any significant relationship exists between a company’s profitability aneither of these two characteristics. Colleen Quinni, asenior analyst the fun suggests thinitistep in his investigation,Varn shoulperform a multiple regression analysis on the variables anreport bato her. Varn knows thQuinni is expert quantitative research, anshe ontolVarn thafter you get iyou shoulformulate a hypothesis, test the hypothesis, ananalyze the results. Varn expects to finthESG rating is negatively relateto ROE anCEO tenure is positively relateto ROE. He consirs a relationship meaningful when it is statistically significant the 0.05 level. To begin, Varn collects values for ROE, CEO tenure, anESG rating for a sample of 40 companies from the large-csecurity universe. He performs a multiple regression with ROE (in percent) the pennt variable anESG rating anCEO tenure (in years) the inpennt variables: Yi = + b1X1i +b2X2i + εi. Exhibit 1 shows the regression results. Associates is one of the companies Varn follows. He wants to preits ROE using his regression mol. Associates’ corporate ESG rating is 55, anthe company’s CEO hbeen in thposition for 10.5 years. Varn also wants to cheon the relationship between these variables anthe vingrowth rate (vgr), so he completes the correlation matrix shown in Exhibit 2.Investigating further, Varn termines thvingrowth is not a linecombination of CEO tenure anESG rating. He is uncleabout how aitioninpennt variables woulaffethe significanof the regression, so he asks Quinni, \"Given this correlation matrix, will both R2 anausteR2 automatically increase if I a vingrowth a thirinpennt variable?\" The scussion continues, anQuinni asks two questions.1.Whes your F-statistic of 4.161 tell you about the regression?2.In interpreting the overall significanof your regression mol, whistatistic you believe is most relevant: R2, austeR2, or the F-statistic?Varn answers both questions correctly ansays he wants to chetwo more ias. He believes the following:1. ROE is less correlatewith the vingrowth rate in firms whose CEO hbeen in offimore th15 years, an.CEO tenure is a normally stributeranm variable.Later, Varn inclus the vingrowth rate a thirinpennt variable anruns the regression on the funs entire group of 500 large-cequities. He fin ththe austeR2 is muhigher ththe results in Exhibit 1. He reports this to Quinni ansays, \"Aing the vingrowth rate gives a mol with a higher austeR2. The three-variable mol is clearly better.\" Quinni cautions, \"I n’t think you cconclu thyet.\" 5. Baseon Exhibit 2, Quinni’s best answer to Varn’s question about the effeof aing a thirinpennt variable is: no for R2 anno for austeR2. yes for R2 anno for austeR2. yes for R2 anyes for austeR2. B is correct. When you a aitioninpennt variable to the regression mol, the amount of unexplainevarianwill crease, provithe new variable explains any of the previously unexplainevariation. This result occurs long the new variable is even slightly correlatewith the pennt variable. Exhibit 2 incates the vingrowth rate is correlatewith the pennt variable, ROE. Therefore, R2 will increase.AusteR2, however, mnot increase anmeven crease if the relationship is weak. This result occurs because in the formula for austeR2, the new variable increases k (the number of inpennt variables) in the nominator, anthe increase in R2 minsufficient to increase the value of the formula.textauste2=1−(n−1n−k−1)(1−R2text{austeR}^\text{2}=1-(\frac{n-1}{n-k-1})(1-R^2textauste2=1−(n−k−1n−1​)(1−R2 老师 麻烦一下这题,为什么选B呀,为什么R^2是yes

2024-01-08 23:40 1 · 回答

NO.PZ201709270100000305 问题如下 5. Baseon Exhibit 2, Quinni’s best answer to Varn’s question about the effeof aing a thirinpennt variable is: no for R2 anno for austeR2. yes for R2 anno for austeR2. yes for R2 anyes for austeR2. B is correct. When you a aitioninpennt variable to the regression mol, the amount of unexplainevarianwill crease, provithe new variable explains any of the previously unexplainevariation. This result occurs long the new variable is even slightly correlatewith the pennt variable. Exhibit 2 incates the vingrowth rate is correlatewith the pennt variable, ROE. Therefore, R2 will increase.AusteR2, however, mnot increase anmeven crease if the relationship is weak. This result occurs because in the formula for austeR2, the new variable increases k (the number of inpennt variables) in the nominator, anthe increase in R2 minsufficient to increase the value of the formula.textauste2=1−(n−1n−k−1)(1−R2text{austeR}^\text{2}=1-(\frac{n-1}{n-k-1})(1-R^2textauste2=1−(n−k−1n−1​)(1−R2 另AustR的变化方向是否以1作为标准?而非0.7?

2023-07-30 20:39 1 · 回答

NO.PZ201709270100000305问题如下 5. Baseon Exhibit 2, Quinni’s best answer to Varn’s question about the effeof aing a thirinpennt variable is: no for R2 anno for austeR2. yes for R2 anno for austeR2. yes for R2 anyes for austeR2. B is correct. When you a aitioninpennt variable to the regression mol, the amount of unexplainevarianwill crease, provithe new variable explains any of the previously unexplainevariation. This result occurs long the new variable is even slightly correlatewith the pennt variable. Exhibit 2 incates the vingrowth rate is correlatewith the pennt variable, ROE. Therefore, R2 will increase.AusteR2, however, mnot increase anmeven crease if the relationship is weak. This result occurs because in the formula for austeR2, the new variable increases k (the number of inpennt variables) in the nominator, anthe increase in R2 minsufficient to increase the value of the formula.textauste2=1−(n−1n−k−1)(1−R2text{austeR}^\text{2}=1-(\frac{n-1}{n-k-1})(1-R^2textauste2=1−(n−k−1n−1​)(1−R2 如题????????????我觉得0.1不小啊

2023-01-26 22:29 1 · 回答

NO.PZ201709270100000305 问题如下 5. Baseon Exhibit 2, Quinni’s best answer to Varn’s question about the effeof aing a thirinpennt variable is: no for R2 anno for austeR2. yes for R2 anno for austeR2. yes for R2 anyes for austeR2. B is correct. When you a aitioninpennt variable to the regression mol, the amount of unexplainevarianwill crease, provithe new variable explains any of the previously unexplainevariation. This result occurs long the new variable is even slightly correlatewith the pennt variable. Exhibit 2 incates the vingrowth rate is correlatewith the pennt variable, ROE. Therefore, R2 will increase.AusteR2, however, mnot increase anmeven crease if the relationship is weak. This result occurs because in the formula for austeR2, the new variable increases k (the number of inpennt variables) in the nominator, anthe increase in R2 minsufficient to increase the value of the formula.textauste2=1−(n−1n−k−1)(1−R2text{austeR}^\text{2}=1-(\frac{n-1}{n-k-1})(1-R^2textauste2=1−(n−k−1n−1​)(1−R2 请问0.117和谁对比?

2023-01-23 00:21 2 · 回答

NO.PZ201709270100000305问题如下 5. Baseon Exhibit 2, Quinni’s best answer to Varn’s question about the effeof aing a thirinpennt variable is: no for R2 anno for austeR2. yes for R2 anno for austeR2. yes for R2 anyes for austeR2. B is correct. When you a aitioninpennt variable to the regression mol, the amount of unexplainevarianwill crease, provithe new variable explains any of the previously unexplainevariation. This result occurs long the new variable is even slightly correlatewith the pennt variable. Exhibit 2 incates the vingrowth rate is correlatewith the pennt variable, ROE. Therefore, R2 will increase.AusteR2, however, mnot increase anmeven crease if the relationship is weak. This result occurs because in the formula for austeR2, the new variable increases k (the number of inpennt variables) in the nominator, anthe increase in R2 minsufficient to increase the value of the formula.textauste2=1−(n−1n−k−1)(1−R2text{austeR}^\text{2}=1-(\frac{n-1}{n-k-1})(1-R^2textauste2=1−(n−k−1n−1​)(1−R2 我感觉这题在考察多重共线性情况下 aust r^2的影响,如果多重共线性发生,自变量之间的 correlation 过高,就会有使得r^2上升,但是a r^2 下降。我是这么理解的,但是这道题,我不知道怎么得出 no for a r^2 的

2022-08-16 07:57 2 · 回答