一季度returen

NO.PZ2022010501000004 问题如下 Use the information in the following table to answer this question (amounts in €):Calculate the rate of return for this portfolio for January, February, March, anthe first quarter of 2019 using revaluing for large cash flows methology (assume “large” is finegreater th5%). January: RJan= (208,000 − 200,000)/200,000 = 4.00%February: RFeb1- 15 = (217,000 − 208,000)/208,000 = 4.33% RFeb16- 28= (263,000 − 257,000)/257,000 = 2.33% RFeb1-28 = [(1 + 0.0433) × (1 + 0.0233)] − 1 = 6.76%March: RMar1- 21 == (270,000 − 263,000)/263,000 = 2.66% RMar22- 31= (245,000 − 240,000)/240,000 = 2.08% RMar1- 31= [(1 + 0.0266) × (1 + 0.0208)] − 1 = 4.80%Quarter 1: RQT1 = [(1 + 0.0400) × (1 + 0.0676) × (1 + 0.0480)] − 1 = 16.36% the rate of return for this portfolio for January=(208000-200000)/200000=4%the rate of return for this portfolio for February(217000-208000)/208000=4.33%(263000-257000)/257000=2.33%(1+4.33%)(1+2.33%)-1=6.76%the rate of return for this portfolio for March(270000-263000)/263000=2.66%(245000-240000)/240000=2.08%(1+2.66%)(1+2.08%)-1=4.80%the first quarter of 2019(1+4%) * (1+6.76%) *(1+4.8%)=16.36%

NO.PZ2022010501000004问题如下 Use the information in the following table to answer this question (amounts in €):Calculate the rate of return for this portfolio for January, February, March, anthe first quarter of 2019 using revaluing for large cash flows methology (assume “large” is finegreater th5%). January: RJan= (208,000 − 200,000)/200,000 = 4.00%February: RFeb1- 15 = (217,000 − 208,000)/208,000 = 4.33% RFeb16- 28= (263,000 − 257,000)/257,000 = 2.33% RFeb1-28 = [(1 + 0.0433) × (1 + 0.0233)] − 1 = 6.76%March: RMar1- 21 == (270,000 − 263,000)/263,000 = 2.66% RMar22- 31= (245,000 − 240,000)/240,000 = 2.08% RMar1- 31= [(1 + 0.0266) × (1 + 0.0208)] − 1 = 4.80%Quarter 1: RQT1 = [(1 + 0.0400) × (1 + 0.0676) × (1 + 0.0480)] − 1 = 16.36% 1.5%是针对每一次资金流入流出时候的fair value而言吗，还是针对初始值2000000？2.如果在某个月有两笔资金流入，一笔高于5%，那么需要先算一个subportfolio return，第二笔低于5%，那么再用mofieetz的方法算第二个subportfolio，然后再把两个sub portfolio结合起来算整个月的收益？能举例阐述下吗？

NO.PZ2022010501000004 问题如下 Use the information in the following table to answer this question (amounts in €):Calculate the rate of return for this portfolio for January, February, March, anthe first quarter of 2019 using revaluing for large cash flows methology (assume “large” is finegreater th5%). January: RJan= (208,000 − 200,000)/200,000 = 4.00%February: RFeb1- 15 = (217,000 − 208,000)/208,000 = 4.33% RFeb16- 28= (263,000 − 257,000)/257,000 = 2.33% RFeb1-28 = [(1 + 0.0433) × (1 + 0.0233)] − 1 = 6.76%March: RMar1- 21 == (270,000 − 263,000)/263,000 = 2.66% RMar22- 31= (245,000 − 240,000)/240,000 = 2.08% RMar1- 31= [(1 + 0.0266) × (1 + 0.0208)] − 1 = 4.80%Quarter 1: RQT1 = [(1 + 0.0400) × (1 + 0.0676) × (1 + 0.0480)] − 1 = 16.36% RFeb1-28 = [(1 + 0.0433) × (1 + 0.0233)] − 1 = 6.76%moetz的公式也不太理解，为什么只坟分母考虑天数分子不考虑时间加权呢

NO.PZ2022010501000004 问题如下 Use the information in the following table to answer this question (amounts in €):Calculate the rate of return for this portfolio for January, February, March, anthe first quarter of 2019 using revaluing for large cash flows methology (assume “large” is finegreater th5%). January: RJan= (208,000 − 200,000)/200,000 = 4.00%February: RFeb1- 15 = (217,000 − 208,000)/208,000 = 4.33% RFeb16- 28= (263,000 − 257,000)/257,000 = 2.33% RFeb1-28 = [(1 + 0.0433) × (1 + 0.0233)] − 1 = 6.76%March: RMar1- 21 == (270,000 − 263,000)/263,000 = 2.66% RMar22- 31= (245,000 − 240,000)/240,000 = 2.08% RMar1- 31= [(1 + 0.0266) × (1 + 0.0208)] − 1 = 4.80%Quarter 1: RQT1 = [(1 + 0.0400) × (1 + 0.0676) × (1 + 0.0480)] − 1 = 16.36% 这样算可以吗？the first quarter: (1+(217-200)/200)*(1+(270-257)/257)*(1+(245-240)/240)-1=16.37%