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mandy · 2025年01月07日

请教一下我的答案和四舍五入的问题

NO.PZ2023032703000086

问题如下:

Alfred Simonsson is assistant treasurer at a Swedish lumber company. The company has sold a large tract of land and now has sufficient cash holdings to retire some of its debt liabilities. The company’s accounting department assures Alfred that its external auditors will approve of a defeasement strategy if Swedish government bonds are purchased to match the interest and principal payments on the liabilities. Following is the schedule of payments due on the debt as of June Year 1 that the company plans to defease:

The following Swedish government bonds are available. Interest on the bonds is paid annually in May of each year.

How much in par value for each government bond will Alfred need to buy to defease the debt liabilities, assuming that the minimum denomination in each security is SEK10,000?

选项:

解释:

Correct Answer:

The cash flow matching portfolio is built by starting with the last liability of SEK5,250,000 in June Year 5.

If there were no minimum denomination, that liability could be funded with the 5.50% bonds due May Year 5 having a par value of SEK4,976,303 (= SEK5,250,000/1.0550). To deal with the constraint, however, Alfred buys SEK4,980,000 in par value.

This holding also pays SEK273,900 (= SEK4,980,000 × 0.0550) in coupon interest in May Year 2, 3, and 4.

Then move to the June Year 4 obligation, which is SEK4,136,100 after subtracting the SEK273,900 received on the 5.50% bond: SEK4,410,000 – SEK273,900 = SEK4,136,100.

Alfred buys SEK3,950,000 in par value of the 4.75% bond due May Year 4. That bond pays SEK4,137,625 (= SEK3,950,000 × 1.0475) at maturity and SEK187,625 in interest in May Year 2 and Year 3.

The net obligation in June Year 3 is SEK6,158,475 (= SEK6,620,000 – SEK273,900 – SEK187,625) after subtracting the interest received on the longer-maturity bonds.

The company can buy SEK5,950,000 in par value of the 3.50% bond due May Year 3. At maturity, this bond pays SEK6,158,250 (= SEK5,950,000 × 1.0350). The small shortfall of SEK225 (= SEK6,158,475 – SEK6,158,250) can be made up because the funds received in May are reinvested until June. This bond also pays SEK208,250 in interest in May Year 2.

Finally, Alfred needs to buy SEK2,960,000 in par value of the 2.75% bond due May Year 2. This bond pays SEK3,041,400 (= SEK2,960,000 × 1.0275) in May Year 2. The final coupon and principal, plus the interest on the 5.50%, 4.75%, and 3.50% bonds, total SEK3,711,175 (= SEK3,041,400 + SEK273,900 + SEK187,625 + SEK208,250). That amount is used to pay off the June Year 2 obligation of SEK3,710,000. Note that the excess could be kept in a bank account to cover the Year 3 shortfall.

In sum, Alfred buys the following portfolio:

1. 老师,请问下这里计算par value也是按照四舍五入的原则吗?比如第三个bond(mature in May Year 3)实际算出来是5950217,我本来以为是为了defease liability 素以par value应该无论如何和其他的coupon加起来应该要超过这一年的liability,但是看答案是四舍五入为5950000了。


2. 以下是我的答案,请问考试中这样回答是否足够?感觉答案写了很多步骤考试中可能没时间写

First Swedish government bonds (mature in May Year 5 with coupon 5.5%) has a par value of SEK4980000.

Second Swedish government bonds (mature in May Year 4 with coupon 4.75%) has a par value of SEK3950000.

Third Swedish government bonds (mature in May Year 3 with coupon 3.5%) has a par value of SEK5950000.

Fourth Swedish government bonds (mature in May Year 2 with coupon 2.75%) has a par value of SEK2960000.

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NO.PZ2023032703000086 问题如下 AlfreSimonsson is assistant treasurera Swesh lumber company. The company hsola large traof lanannowhsufficient cash holngs to retire some of its liabilities. Thecompany’s accounting partment assures Alfrethits externautors willapprove of a feasement strategy if Swesh government bon are purchasetomatthe interest anprincippayments on the liabilities. Following is theschele of payments e on the of June Ye1 ththe company plans tofease:The followingSwesh government bon are available. Interest on the bon is paiannuallyin Mof eayear.How muin parvalue for eagovernment bonwill Alfreneeto buy to fease the btliabilities, assuming ththe minimum nomination in easecurity isSEK10,000? CorreAnswer:The cash flow matching portfolio is built starting with the last liability of SEK5,250,000 in June Ye5.If there were no minimum nomination, thliability coulfunwith the 5.50% bon e MYe5 having a pvalue of SEK4,976,303 (= SEK5,250,000/1.0550). To with the constraint, however, Alfrebuys SEK4,980,000 in pvalue.This holng also pays SEK273,900 (= SEK4,980,000 × 0.0550) in coupon interest in MYe2, 3, an4.Then move to the June Ye4 obligation, whiis SEK4,136,100 after subtracting the SEK273,900 receiveon the 5.50% bon SEK4,410,000 – SEK273,900 = SEK4,136,100.Alfrebuys SEK3,950,000 in pvalue of the 4.75% bone MYe4. Thbonpays SEK4,137,625 (= SEK3,950,000 × 1.0475) maturity anSEK187,625 in interest in MYe2 anYe3.The net obligation in June Ye3 is SEK6,158,475 (= SEK6,620,000 – SEK273,900 – SEK187,625) after subtracting the interest receiveon the longer-maturity bon.The company cbuy SEK5,950,000 in pvalue of the 3.50% bone MYe3. maturity, this bonpays SEK6,158,250 (= SEK5,950,000 × 1.0350). The small shortfall of SEK225 (= SEK6,158,475 – SEK6,158,250) cma up because the fun receivein Mare reinvesteuntil June. This bonalso pays SEK208,250 in interest in MYe2.Finally, Alfrenee to buy SEK2,960,000 in pvalue of the 2.75% bone MYe2. This bonpays SEK3,041,400 (= SEK2,960,000 × 1.0275) in MYe2. The fincoupon anprincipal, plus the interest on the 5.50%, 4.75%, an3.50% bon, totSEK3,711,175 (= SEK3,041,400 + SEK273,900 + SEK187,625 + SEK208,250). Thamount is useto poff the June Ye2 obligation of SEK3,710,000. Note ththe excess coulkept in a bank account to cover the Ye3 shortfall.In sum, Alfrebuys the following portfolio: The cash flow matching portfolio is built starting with the last liability of SEK5,250,000 in June Ye5.If there were no minimum nomination, thliability coulfunwith the 5.50% bon e MYe5 having a pvalue of SEK4,976,303 (= SEK5,250,000/1.0550). To with the constraint, however, Alfrebuys SEK4,980,000 in pvalue.题中给的5.5 不是coupon rate 么? FV 是5250 000, PV计算不是需要PMT和YI么?PMT 不是 coupon 么?为什么这个题目用这种方式MYe5 having a pvalue of SEK4,976,303 (= SEK5,250,000/1.0550).

2025-01-06 17:17 1 · 回答