开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

梦梦 · 2024年06月01日

如果给的不是30呢?

NO.PZ2023091601000058

问题如下:

A risk manager is examining a Hong Kong trader’s profit and loss record for the last week, as shown in the table below:

The profits and losses are normally distributed with a mean of 4.5 million HKD and assume that transaction costs can be ignored. Part of the t-table is provided below:

According to the information provided above, what is the probability that this trader will record a profit of at least HKD 30 million on the first trading day of next week?

选项:

A.

About 15%

B.

About 20%

C.

About 80%

D.

About 85%

解释:

When the population mean and population variance are not known, the t-statistic can be used to analyze the distribution of the sample mean.

Sample mean = (10 + 80 + 90 - 60 + 30)/5 = 30

Unbiased sample variance = (1/4)[ (-20)^2 + 50^2 + 60^2 + (-90)^2 + 0^2 ] = 14600/4 = 3650

Unbiased sample standard deviation = 60.4152

Sample standard error = (sample standard deviation)/√5 = 27.0185

Population mean of return distribution = 4.5 (million HKD)

Therefore the t-statistic = (30 – population mean)/Sample standard error = (30 - 4.5)/27.02 = 0.9438.

Because we are using the sample mean in the analysis, we must remove 1 degree of freedom before consulting the t-table; therefore 4 degrees of freedom are used. According to the table, the closest possibility is 0.2 = 20%.

老师好,这道题的at least 30 on the first trading day of the next week,如果给的不是30呢?还能这样做吗?


3 个答案

品职答疑小助手雍 · 2024年06月05日

换个角度想,你就把每次检验当做检验均值……

毕竟对正态或者t分布这种对称的分布的检验,标准化的过程都是一样的。减均值之后除以标准差,看分位点

梦梦 · 2024年06月06日

好的

品职答疑小助手雍 · 2024年06月03日

那就太死板了,你列出来的那个公式是对估计的样本均值的假设检验,原理都是计算分位点,看拒绝域。

那用其他值也可以进行这种操作的。

梦梦 · 2024年06月04日

😂😂😂😂😂😂

品职答疑小助手雍 · 2024年06月02日

同学你好,不是30也可以的,只要是检验一个数值,都可以用这个步骤完成标准化,找到分位点,然后在分布表里找分位点对应的概率。

梦梦 · 2024年06月02日

那t分布的公式应该是样本均值减去估计的总体均值后除标准误,如果不是30,为什么也能用t分布公式呢,毕竟不是样本均值耶

  • 3

    回答
  • 0

    关注
  • 224

    浏览
相关问题

NO.PZ2023091601000058问题如下 A risk manager is examining aHong Kong trar’s profit anloss recorfor the last week, shown in thetable below:The profits anosses are normally stributewith a meof 4.5 million HKanassume thattransaction costs cignore Part of the t-table is provibelow: Accorngto the information proviabove, whis the probability ththis trarwill recora profit of least HK30 million on the first trang y ofnext week? A.About 15% B.About 20% C.About 80% About 85% When the populationmeanpopulation varianare not known, the t-statistic cusetoanalyze the stribution of the sample mean. Sample me= (10 +80 + 90 - 60 + 30)/5 = 30 Unbiasesamplevarian= (1/4)[ (-20)^2 + 50^2 + 60^2 + (-90)^2 + 0^2 ] = 14600/4 = 3650 Unbiasesamplestanrviation = 60.4152 Sample stanrerror= (sample stanrviation)/√5 = 27.0185 Population meofreturn stribution = 4.5 (million HK Therefore thet-statistic = (30 – population mean)/Sample stanrerror = (30 - 4.5)/27.02 =0.9438. Because we are usingthe sample mein the analysis, we must remove 1 gree of freem beforeconsulting the t-table; therefore 4 grees of freem are use Accorng tothe table, the closest possibility is 0.2 = 20%. 1、这道题就是求P(X=30million)吧?而不是P(X大于等于30million)?2、为什么30减去的是总体均值,而不是样本均值?

2024-11-09 22:08 2 · 回答

NO.PZ2023091601000058 问题如下 A risk manager is examining aHong Kong trar’s profit anloss recorfor the last week, shown in thetable below:The profits anosses are normally stributewith a meof 4.5 million HKanassume thattransaction costs cignore Part of the t-table is provibelow: Accorngto the information proviabove, whis the probability ththis trarwill recora profit of least HK30 million on the first trang y ofnext week? A.About 15% B.About 20% C.About 80% About 85% When the populationmeanpopulation varianare not known, the t-statistic cusetoanalyze the stribution of the sample mean. Sample me= (10 +80 + 90 - 60 + 30)/5 = 30 Unbiasesamplevarian= (1/4)[ (-20)^2 + 50^2 + 60^2 + (-90)^2 + 0^2 ] = 14600/4 = 3650 Unbiasesamplestanrviation = 60.4152 Sample stanrerror= (sample stanrviation)/√5 = 27.0185 Population meofreturn stribution = 4.5 (million HK Therefore thet-statistic = (30 – population mean)/Sample stanrerror = (30 - 4.5)/27.02 =0.9438. Because we are usingthe sample mein the analysis, we must remove 1 gree of freem beforeconsulting the t-table; therefore 4 grees of freem are use Accorng tothe table, the closest possibility is 0.2 = 20%. 有个小问题,这个题目给的t分布查表是不是单尾的呢?

2024-11-02 11:20 1 · 回答