这题在新考纲范围内嘛

NO.PZ2020010303000013

问题如下：

If the kurtosis of some returns on a small-cap stock portfolio was 6, what would the degrees of freedom parameter be if they were generated by a generalized Student’s $t_\upsilon$ ? What if the kurtosis was 9?

选项：

解释：

In a Student’s t, the kurtosis depends only on the degree of freedom and is k = 3(v-2)/( v-4).

This can be solved so that k(v - 4) = 3(v - 2) so that kv - 4k = 3v - 6 and kv - 3v = 4k - 6.

Finally, solving for v, v =(4k-6)/ (k-3)

Plugging in v =(24-6)/(6-3)=18/3=6 and v =(36-6)/ (9-3)= 5.

The degree of freedom is v-1.

The kurtosis falls rapidly as v grows.

For example, if v = 12 then k = 3.75, which is only slightly higher than the kurtosis of a normal (3).

这题在新考纲范围内嘛

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李坏_品职助教 · 2024年05月03日

嗨，爱思考的PZer你好：

这个在新考纲里面依然是需要掌握的考点，建议同学可以看一下“Mixture Distribution”这部分的Example 4的讲解：

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加油吧，让我们一起遇见更好的自己！

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这题在新考纲范围内嘛

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