开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

徐威廉 · 2024年04月23日

这是个什么公式?

NO.PZ2023090501000051

问题如下:

A risk analyst at a bank is estimating the distribution of credit losses for a portfolio of 30 identical loan exposures. The analyst assumes that the credit losses follow a binomial distribution. Each loan has the following characteristics:

Amount: SGD 500,000

Probability of default: 4%

Recovery rate: 30%

Average pairwise default correlation: 0.4

What is the standard deviation of losses on the loan portfolio expressed as a percentage of the size of the portfolio?

选项:

A.

3.8%

B.

5.8%

C.

7.8%

D.

8.9%

解释:

Explanation

D is correct. The standard deviation of losses for each individual loan is:


where p represents probability of default, Li represents exposure at default (amount borrowed), and Ri represents recovery rate.

The standard deviation of losses on the portfolio of n loans as a percentage of its size is then calculated as:


A is incorrect. This uses the incorrect formula for standard deviation of losses of the in dividual loans

B is incorrect. This uses the incorrect formula for standard deviation of losses on the portfolio

C is incorrect. This uses the incorrect formula for standard deviation of losses on

the portfolio

Section Valuation and Risk Models

Learning Objective Estimate the mean and standard deviation of credit losses assuming a binomial distribution.

Reference Global Association of Risk Professionals. Valuation and Risk Models. New York, NY: Pearson, 2022. Chapter 6. Measuring Credit Risk.

这是个什么公式?

1 个答案
已采纳答案

李坏_品职助教 · 2024年04月24日

嗨,爱思考的PZer你好:


这道题和前面你问过的另一个standard deviation of loss的题目很类似,区别在于,上一道题求的是金额为单位的standard deviation,而且loan是不一样的。

而本题求的是“as a percentage of the size”,也就是比率形式的standard deviation,而且本题的loan都是一样的。



先用红框公式1计算每一个loan单独的σ, σ = 根号(0.04-0,04^2)*[500000*(1-30%)] = 68585.71,

然后利用红框公式2求出α。 α = σ * 根号(1+(n-1)*ρ) / (L * 根号n), 这里的L就是每一个loan的amount 500000, ρ是相关系数0.4, n是贷款的数量30。

----------------------------------------------
虽然现在很辛苦,但努力过的感觉真的很好,加油!

  • 1

    回答
  • 0

    关注
  • 143

    浏览
相关问题