利率二叉树求解

NO.PZ2019010402000022 问题如下 Baseon the following information, the value of the European-style interest rate call option is:Assume the notionamount of the option is $1,000,000, the exercise rate is 2.6% anthe RN probability is 50%. A.2,368 B.2,529 C.3,675 B is correct.考点interest rate option估值解析T=2:c++ = Max(0,S++ – X) = Max[0,0.029833– 0.026] = 0.003833c+– = Max(0,S+– – X) = Max[0,0.029378 – 0.026] = 0.003378– = Max(0,S– – – X) = Max[0,0.015712 – 0.026] = 0.0T=1:c+=0.5×0.003833+0.5×0.0033781+2.9156%=0.003503c^+=\frac{0.5\times0.003833+0.5\times0.003378}{1+2.9156\%}=0.003503c+=1+2.9156%0.5×0.003833+0.5×0.003378​=0.003503c−=0.5×0.003378+01+1.7632%=0.001660c^-=\frac{0.5\times0.003378+0}{1+1.7632\%}=0.001660c−=1+1.7632%0.5×0.003378+0​=0.001660T=0c0=0.003503×0.5+0.001660×0.51+2.0689%=0.002529{\text{c}}_0=\frac{0.003503\times0.5+0.001660\times0.5}{1+2.0689\%}=0.002529c0​=1+2.0689%0.003503×0.5+0.001660×0.5​=0.002529因为NP=1,000,000，所以call value=0.002529×1,000,000=2,529.17在计算interest rate option value的时候，一定要特别注意折现率的选取。 请问这个call或者put行权与否怎么判断的？

NO.PZ2019010402000022 问题如下 Baseon the following information, the value of the European-style interest rate call option is:Assume the notionamount of the option is $1,000,000, the exercise rate is 2.6% anthe RN probability is 50%. A.2,368 B.2,529 C.3,675 B is correct.考点interest rate option估值解析T=2:c++ = Max(0,S++ – X) = Max[0,0.029833– 0.026] = 0.003833c+– = Max(0,S+– – X) = Max[0,0.029378 – 0.026] = 0.003378– = Max(0,S– – – X) = Max[0,0.015712 – 0.026] = 0.0T=1:c+=0.5×0.003833+0.5×0.0033781+2.9156%=0.003503c^+=\frac{0.5\times0.003833+0.5\times0.003378}{1+2.9156\%}=0.003503c+=1+2.9156%0.5×0.003833+0.5×0.003378​=0.003503c−=0.5×0.003378+01+1.7632%=0.001660c^-=\frac{0.5\times0.003378+0}{1+1.7632\%}=0.001660c−=1+1.7632%0.5×0.003378+0​=0.001660T=0c0=0.003503×0.5+0.001660×0.51+2.0689%=0.002529{\text{c}}_0=\frac{0.003503\times0.5+0.001660\times0.5}{1+2.0689\%}=0.002529c0​=1+2.0689%0.003503×0.5+0.001660×0.5​=0.002529因为NP=1,000,000，所以call value=0.002529×1,000,000=2,529.17在计算interest rate option value的时候，一定要特别注意折现率的选取。 c+和不需要=max(0,s-x)吗？

NO.PZ2019010402000022问题如下Baseon the following information, the value of the European-style interest rate call option is:Assume the notionamount of the option is $1,000,000, the exercise rate is 2.6% anthe RN probability is 50%.A.2,368B.2,529C.3,675B is correct.考点interest rate option估值解析T=2:c++ = Max(0,S++ – X) = Max[0,0.029833– 0.026] = 0.003833c+– = Max(0,S+– – X) = Max[0,0.029378 – 0.026] = 0.003378– = Max(0,S– – – X) = Max[0,0.015712 – 0.026] = 0.0T=1:c+=0.5×0.003833+0.5×0.0033781+2.9156%=0.003503c^+=\frac{0.5\times0.003833+0.5\times0.003378}{1+2.9156\%}=0.003503c+=1+2.9156%0.5×0.003833+0.5×0.003378​=0.003503c−=0.5×0.003378+01+1.7632%=0.001660c^-=\frac{0.5\times0.003378+0}{1+1.7632\%}=0.001660c−=1+1.7632%0.5×0.003378+0​=0.001660T=0c0=0.003503×0.5+0.001660×0.51+2.0689%=0.002529{\text{c}}_0=\frac{0.003503\times0.5+0.001660\times0.5}{1+2.0689\%}=0.002529c0​=1+2.0689%0.003503×0.5+0.001660×0.5​=0.002529因为NP=1,000,000，所以call value=0.002529×1,000,000=2,529.17在计算interest rate option value的时候，一定要特别注意折现率的选取。如题 当时看视频的时候也注意到这个了

NO.PZ2019010402000022 这个利率两期看涨期权二叉树，给出来的话，是什么意思，我分不清这个现金流的问题，我算的话是 算出C++=2.9833%-2.6%=0.3833%，然后拿0.3833%/(1+2.9833%)=0.3722%，认为c++在t2时刻是=0.3722%， 但我这样算是错的， 答案是直接c++在t2==2.9833%-2.6%=0.3833% 疑问→为什么算c++不需要用t2的折现率去折现