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NO.PZ2015120604000147

问题如下：

Here is a table discribing sample statistics from two bonds' rate of return which are both normally distributed over the past decades. If an investor is considering whether the mean of bond B is greater than 26%,

which of the following conclusion is least appropriate (significant level=5%) ?

选项：

It is appropriate to use the Z-test.

The mean of bond B is not significant greater than 26%.

It is a one-tailed test.

解释：

B is correct.

It is appropraite to ues the one-tailed Z-test because the sample size of bond B is bigger than 30.

The null hypothesis is: $H_{0} : μ$ ≤ $26%$

The test statistic:

α= 5% indicates the critical value is equal to ±1.65.

Because 1.91>1.65, therefore, we should reject the null hypothesis.

请问对于这道题大样本的情况，计算出来t统计量后查对应的5%的critical value是不是既可以查z分布表也可以查t分布表

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品职助教_七七 · 2024年03月13日

嗨，从没放弃的小努力你好：

可以的。

对于简单只是判断大小的问题，t分布和z分布的关键值相差无几，不会影响到最终的判断结果。

本题可以直接使用正态分布的关键值1.65，省去查表的步骤和时间。

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