问题如下图：
选项：
A. 
B. 
C. 
解释：
老师，请问C选项怎么理解？
NO.PZ2017092702000140 问题如下 investment consultant concts two inpennt ranm samples of 5-yeperformanta for US anEuropeabsolute return hee fun. Noting a 50 basis point return aantage for US managers, the consultant cis to test whether the two means are statistically fferent from one another a 0.05 level of significance. The two populations are assumeto normally stributewith unknown but equvariances. Results of the hypothesis test are containein the tables below.The results of the hypothesis test incate ththe: A.null hypothesis is not rejecte B.alternative hypothesis is statistically confirme C.fferenin mereturns is statistically fferent from zero. A is correct. The t-statistic value of 0.4893 es not fall into the criticvalue rejection regions (≤ –1.984 or 1.984). Insteit falls well within the acceptanregion. Thus, H0 cannot rejecte the result is not statistically significant the 0.05 level.t检验的拒绝原假设逻辑为|test statistic|＞|criticvalue|，根据这个原则，直接选择A，无法拒绝原假设。 麻烦老师讲解一下题干和表格，答案会选，题目考察的是什么意思不理解，谢谢
NO.PZ2017092702000140 问题如下 investment consultant concts two inpennt ranm samples of 5-yeperformanta for US anEuropeabsolute return hee fun. Noting a 50 basis point return aantage for US managers, the consultant cis to test whether the two means are statistically fferent from one another a 0.05 level of significance. The two populations are assumeto normally stributewith unknown but equvariances. Results of the hypothesis test are containein the tables below.The results of the hypothesis test incate ththe: A.null hypothesis is not rejecte B.alternative hypothesis is statistically confirme C.fferenin mereturns is statistically fferent from zero. A is correct. The t-statistic value of 0.4893 es not fall into the criticvalue rejection regions (≤ –1.984 or 1.984). Insteit falls well within the acceptanregion. Thus, H0 cannot rejecte the result is not statistically significant the 0.05 level.t检验的拒绝原假设逻辑为|test statistic|＞|criticvalue|，根据这个原则，直接选择A，无法拒绝原假设。 来细说下
NO.PZ2017092702000140问题如下 investment consultant concts two inpennt ranm samples of 5-yeperformanta for US anEuropeabsolute return hee fun. Noting a 50 basis point return aantage for US managers, the consultant cis to test whether the two means are statistically fferent from one another a 0.05 level of significance. The two populations are assumeto normally stributewith unknown but equvariances. Results of the hypothesis test are containein the tables below.The results of the hypothesis test incate ththe:A.null hypothesis is not rejecte B.alternative hypothesis is statistically confirme C.fferenin mereturns is statistically fferent from zero. A is correct. The t-statistic value of 0.4893 es not fall into the criticvalue rejection regions (≤ –1.984 or 1.984). Insteit falls well within the acceptanregion. Thus, H0 cannot rejecte the result is not statistically significant the 0.05 level.t检验的拒绝原假设逻辑为|test statistic|＞|criticvalue|，根据这个原则，直接选择A，无法拒绝原假设。 这题怎么分析没有看懂
NO.PZ2017092702000140 问题如下 investment consultant concts two inpennt ranm samples of 5-yeperformanta for US anEuropeabsolute return hee fun. Noting a 50 basis point return aantage for US managers, the consultant cis to test whether the two means are statistically fferent from one another a 0.05 level of significance. The two populations are assumeto normally stributewith unknown but equvariances. Results of the hypothesis test are containein the tables below.The results of the hypothesis test incate ththe: A.null hypothesis is not rejecte B.alternative hypothesis is statistically confirme C.fferenin mereturns is statistically fferent from zero. A is correct. The t-statistic value of 0.4893 es not fall into the criticvalue rejection regions (≤ –1.984 or 1.984). Insteit falls well within the acceptanregion. Thus, H0 cannot rejecte the result is not statistically significant the 0.05 level.t检验的拒绝原假设逻辑为|test statistic|＞|criticvalue|，根据这个原则，直接选择A，无法拒绝原假设。 b的意思看不懂
NO.PZ2017092702000140问题如下investment consultant concts two inpennt ranm samples of 5-yeperformanta for US anEuropeabsolute return hee fun. Noting a 50 basis point return aantage for US managers, the consultant cis to test whether the two means are statistically fferent from one another a 0.05 level of significance. The two populations are assumeto normally stributewith unknown but equvariances. Results of the hypothesis test are containein the tables below.The results of the hypothesis test incate ththe:A.null hypothesis is not rejecte B.alternative hypothesis is statistically confirme C.fferenin mereturns is statistically fferent from zero. A is correct. The t-statistic value of 0.4893 es not fall into the criticvalue rejection regions (≤ –1.984 or 1.984). Insteit falls well within the acceptanregion. Thus, H0 cannot rejecte the result is not statistically significant the 0.05 level.t检验的拒绝原假设逻辑为|test statistic|＞|criticvalue|，根据这个原则，直接选择A，无法拒绝原假设。 老师，请问下这道题significanlevel是0.05那就是1.96是不是1.984也可以跟1.96比较，结论是不能拒绝。
