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fdzh · 2023年10月30日

烦请解释一下这题

NO.PZ2023091601000034

问题如下:

An operational risk manager uses the Poisson distribution to estimate the frequency of losses in excess of USD 2 million during the next year. It is observed that the frequency of losses greater than USD 2 million is three per year on average over the last 10 years. Assuming that this observation is indicative of future occurrences and that the probability of one event occurring is independent of all other events, what is the probability of five losses in excess of USD 2 million occurring during the next two years?

选项:

A.

10.08%

B.

14.04%

C.

14.62%

D.

16.06%

解释:

最后计算的数字太大,算不出来

1 个答案

品职答疑小助手雍 · 2023年10月31日

同学你好,这题数字不算大的,6^5=7776.

7776/5/4/3/2=64.8.

e^(-6)=0.00247875 直接乘以64.8 得到16.06%

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