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家家 · 2018年06月10日

问一道题:NO.PZ2016062402000005 [ FRM I ]

问题如下图:

选项:t

A.

B.

C.

D.

解释:

答案C没看懂,能再解释详细些吗

1 个答案

orange品职答疑助手 · 2018年06月10日

同学你好,推导过程请见图片


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NO.PZ2016062402000005 问题如下 Given thx any are ranm variables anc anare constants, whione of the following finitions is wrong? A.E(ax+by+c)=aE(x)+bE(y)+cE{(ax+by+c)}=aE{(x)}+bE{(y)}+cE(ax+by+c)=aE(x)+bE(y)+c ,if x any are correlate B.V(ax+by+c)=V(ax+by)+cV{(ax+by+c)}=V{(ax+by)}+cV(ax+by+c)=V(ax+by)+c,if x any are correlate C.Cov(ax+by,cx+)=acV(x)+b(y)+(abc)Cov(x,y)Cov{(ax+by,cx+)}=acV{(x)}+b{(y)}+{(abc)}Cov{(x,y)}Cov(ax+by,cx+)=acV(x)+b(y)+(abc)Cov(x,y),if x any are correlate V(x−y)=V(x+y)=V(x)+V(y)V{(x-y)}=V{(x+y)}=V{(x)}+V{(y)}V(x−y)=V(x+y)=V(x)+V(y), if x any are uncorrelate Statement , it is a lineoperation. Statement C is correct, in Equation: V(Y)=σp2V(Y)=\sigma_p^2V(Y)=σp2​=∑i=1nωi2σi2+∑i=1N∑j=1,j≠iNωiωjσi,j=\sum_{i=1}^n\omega_i^2\sigma_i^2+\sum_{i=1}^N\sum_{j=1,j\neq i}^N\omega_i\omega_j\sigma_{i,j}=∑i=1n​ωi2​σi2​+∑i=1N​∑j=1,j​=iN​ωi​ωj​σi,j​=∑i=1Nωi2σi2+2∑i=1N∑j iNωiωjσi,j=\sum_{i=1}^N\omega_i^2\sigma_i^2+2\sum_{i=1}^N\sum_{j i}^N\omega_i\omega_j\sigma_{i,j}=∑i=1N​ωi2​σi2​+2∑i=1N​∑j iN​ωi​ωj​σi,j​Statement is correct, the covarianterm is zero if the variables are uncorrelate Statement B is false, aing a constant c to a variable cannot change the variance. The constant ops out because it is also in the expectation. Statement B is false, aing a constant c to a variable cannot change the variance.

2024-04-07 16:05 1 · 回答

NO.PZ2016062402000005问题如下Given thx any are ranm variables anc anare constants, whione of the following finitions is wrong?A.E(ax+by+c)=aE(x)+bE(y)+cE{(ax+by+c)}=aE{(x)}+bE{(y)}+cE(ax+by+c)=aE(x)+bE(y)+c ,if x any are correlateB.V(ax+by+c)=V(ax+by)+cV{(ax+by+c)}=V{(ax+by)}+cV(ax+by+c)=V(ax+by)+c,if x any are correlateC.Cov(ax+by,cx+)=acV(x)+b(y)+(abc)Cov(x,y)Cov{(ax+by,cx+)}=acV{(x)}+b{(y)}+{(abc)}Cov{(x,y)}Cov(ax+by,cx+)=acV(x)+b(y)+(abc)Cov(x,y),if x any are correlateV(x−y)=V(x+y)=V(x)+V(y)V{(x-y)}=V{(x+y)}=V{(x)}+V{(y)}V(x−y)=V(x+y)=V(x)+V(y), if x any are uncorrelateStatement , it is a lineoperation. Statement C is correct, in Equation: V(Y)=σp2V(Y)=\sigma_p^2V(Y)=σp2​=∑i=1nωi2σi2+∑i=1N∑j=1,j≠iNωiωjσi,j=\sum_{i=1}^n\omega_i^2\sigma_i^2+\sum_{i=1}^N\sum_{j=1,j\neq i}^N\omega_i\omega_j\sigma_{i,j}=∑i=1n​ωi2​σi2​+∑i=1N​∑j=1,j​=iN​ωi​ωj​σi,j​=∑i=1Nωi2σi2+2∑i=1N∑j iNωiωjσi,j=\sum_{i=1}^N\omega_i^2\sigma_i^2+2\sum_{i=1}^N\sum_{j i}^N\omega_i\omega_j\sigma_{i,j}=∑i=1N​ωi2​σi2​+2∑i=1N​∑j iN​ωi​ωj​σi,j​Statement is correct, the covarianterm is zero if the variables are uncorrelate Statement B is false, aing a constant c to a variable cannot change the variance. The constant ops out because it is also in the expectation.老师好,请问c是怎么推导出来的

2024-03-29 14:02 1 · 回答

NO.PZ2016062402000005 问题如下 Given thx any are ranm variables anc anare constants, whione of the following finitions is wrong? A.E(ax+by+c)=aE(x)+bE(y)+cE{(ax+by+c)}=aE{(x)}+bE{(y)}+cE(ax+by+c)=aE(x)+bE(y)+c ,if x any are correlate B.V(ax+by+c)=V(ax+by)+cV{(ax+by+c)}=V{(ax+by)}+cV(ax+by+c)=V(ax+by)+c,if x any are correlate C.Cov(ax+by,cx+)=acV(x)+b(y)+(abc)Cov(x,y)Cov{(ax+by,cx+)}=acV{(x)}+b{(y)}+{(abc)}Cov{(x,y)}Cov(ax+by,cx+)=acV(x)+b(y)+(abc)Cov(x,y),if x any are correlate V(x−y)=V(x+y)=V(x)+V(y)V{(x-y)}=V{(x+y)}=V{(x)}+V{(y)}V(x−y)=V(x+y)=V(x)+V(y), if x any are uncorrelate Statement , it is a lineoperation. Statement C is correct, in Equation: V(Y)=σp2V(Y)=\sigma_p^2V(Y)=σp2​=∑i=1nωi2σi2+∑i=1N∑j=1,j≠iNωiωjσi,j=\sum_{i=1}^n\omega_i^2\sigma_i^2+\sum_{i=1}^N\sum_{j=1,j\neq i}^N\omega_i\omega_j\sigma_{i,j}=∑i=1n​ωi2​σi2​+∑i=1N​∑j=1,j​=iN​ωi​ωj​σi,j​=∑i=1Nωi2σi2+2∑i=1N∑j iNωiωjσi,j=\sum_{i=1}^N\omega_i^2\sigma_i^2+2\sum_{i=1}^N\sum_{j i}^N\omega_i\omega_j\sigma_{i,j}=∑i=1N​ωi2​σi2​+2∑i=1N​∑j iN​ωi​ωj​σi,j​Statement is correct, the covarianterm is zero if the variables are uncorrelate Statement B is false, aing a constant c to a variable cannot change the variance. The constant ops out because it is also in the expectation. B项展开的公式是什么?这部分讲义讲的比较简单,何老师没有展开讲,做题时感觉都不会

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NO.PZ2016062402000005 请问讲义第几页讲了相关知识

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B的正确版本是不是Var(ax+by+c)=Var(ax+by)?

2020-03-17 14:54 1 · 回答