NO.PZ2017092702000081
问题如下:
In a discrete uniform distribution with 20 potential outcomes of integers 1 to 20, the probability that X is greater than or equal to 3 but less than 6, P(3 ≤ X < 6), is:
选项:
A.0.10
B.0.15
C.0.20
解释:
B is correct.
The probability of any outcome is 0.05, P(1) = 1/20 = 0.05. The probability that X is greater than or equal to 3 but less than 6, which is expressed as P(3 ≤ X < 6) = P(3) + P(4) + P(5) = 0.05 + 0.05 + 0.05 = 0.15
本题目的在于从1到20个数字里抽数,问抽出一个数字,且这个数字在3到6这个区间里的概率是多少。
抽出一个数字3的概率就是1/20,抽出数字4的概率就是1/20,抽出一个数字5的概率就是1/2。
所以以把所有的可能性都加起来就是 P(3) + P(4) + P(5) = 0.05 + 0.05 + 0.05 = 0.15
如标题