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Ime · 2018年06月04日

问一道题:NO.PZ2016062402000016

问题如下图:

    

选项:

A.

B.

C.

D.

解释:


不太理解为什么是成功的概率越大 才会越趋近于正太分布,不是越小吗?

1 个答案

orange品职答疑助手 · 2018年06月05日

同学你好,个人认为这里的成功率,说的不是二项分布里的那个p,而是泊松分布里的那个λ.


泊松分布的参数λ是单位时间(或单位面积)内随机事件的平均发生率,它等于n*p。当n足够大时,泊松分布就可以用正态分布来近似,而此时,λ也因为n的增大而增大,最终趋向于它的最大值也就是1


Ime · 2018年06月05日

有道理 成功的概率应该是指的期望 泊松分布的期望就是np

orange品职答疑助手 · 2018年06月05日

加油:-p

omegayin · 2018年10月12日

为啥lamda的最大值是1啊?

omegayin · 2018年10月12日

泊松分布的期望不是成功的次数么……我查了文献,lamda趋近无穷大时,泊松分布的极限分布才是正态分布。答案有问题,应该选D。http://m.baidu.com/sf_edu_wenku/view/5d9ac306e87101f69e3195e4.html

omegayin · 2018年10月12日

呃,稍微修正一下刚才的结论:答案应该选C没错,是因为n足够大、p接近1的时候,lamda=np一定能够保证足够大,使得泊松分布可用正态分布近似。D选项的问题是,p接近于0的时候,即使n很大,也无法保证lamda=np足够大(例如假设p=1/n的情形,此时即使n很大,也只有lamda=1,泊松分布无法近似为正态分布)。

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