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张文文 · 2023年08月23日

请问这里为什么不需要年化除以4呢?

NO.PZ2023020101000014

问题如下:

Whitney’s first meeting is with Novatel, a US based company that currently has an outstanding loan of $250,000,000 that carries a 5.15% fixed interest rate. Novatel’s managers feel that the current interest rate on the loan is high and they also believe that interest rates are poised to decline. Whitney advises Novatel to enter into a one-year pay-floating Libor receive-fixed interest rate swap with quarterly payments. The notional principal on the swap will be $250,000,000. Whitney’s first task is to determine the appropriate swap rate.Ninety days have passed since Whitney’s initial meetings, and in the interim interest rates have increased dramatically. Whitney’s clients have asked to meet with her to review their positions.In order to prepare for the meeting, Whitney has obtained updated interest rate data that is presented in Exhibit 2.Exhibit 2 Term Structure of Rates 90 Days Later (%)

Using data in Exhibit 2 and a 30/360 day count, the market value of Novatel’s swap after 90 days is closest to:

选项:

A.

–$602,250.

B.

–$2,875,000.

C.

–$2,408,880.

解释:

The present value factors for Exhibit 2 are provided below:

For example, PV(180) is calculated as:

11+0.0262×(180/360)=0.987069\frac1{1+0.0262\times(180/360)}=0.987069

Other present value factors are calculated in a similar manner.

Using the fixed rate initially determined for the swap and the current PV factors, the current value of the fixed bond is:

FB=Ci=1nPVt,ti(1)+PV0,tn=0.008396(0.994505+0.987069+0.972786)+0.972786=0.997591FB=C\sum_{i=1}^nPV_{t,ti}(1)+PV_{0,t_n}=0.008396(0.994505+0.987069+0.972786)+0.972786=0.997591

The value of the floating rate bond at reset is 1. The market value of the pay-floating, receive fixed rate swap is the value of the fixed-rate bond less the value of the floating-rate bond, or $250,000,000 × (0.997591 – 1.000) = –$602,250.

Using an alternative approach, the new fixed swap rate would be

rFIX=1.0PV0,tn(1)i=1nPV0,tn(1)=1.00.972786/0.994505+0.987069+0.972786=0.009211r_{FIX}=\frac{1.0-PV_{0,t_n}(1)}{\sum_{i=1}^nPV_{0,t_n}(1)}=1.0-0.972786/0.994505+0.987069+0.972786=0.009211

And the value of the swap is the difference between the value at the old rate and the value at the new rate, or

V=(FS0FSt)i=1nPVt,ti=(0.0083960.009211)×(0.9945+0.9871+0.9728)=0.002409V=(FS_0-FS_t)\sum_{i=1}^nPV_{t,t_i}=(0.008396-0.009211)\times(0.9945+0.9871+0.9728)=-0.002409

The swap value = $250,000,000 × –0.002409 = –$602,250

请问这里为什么不需要年化除以4呢?

1 个答案

Lucky_品职助教 · 2023年08月25日

嗨,努力学习的PZer你好:


本题的swap就是个一年期的swap,不需要除以4

enter into a one-year pay-floating Libor receive-fixed interest rate swap

----------------------------------------------
努力的时光都是限量版,加油!

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NO.PZ2023020101000014 问题如下 Whitney’s first meeting is with Novatel, aUS basecompany thcurrently houtstanng loof $250,000,000 thatcarries a 5.15% fixeinterest rate. Novatel’s managers feel ththe current interestrate on the lois high anthey also believe thinterest rates are poiseo cline. Whitney aises Novatel to enter into a one-yepay-floating Liborreceive-fixeinterest rate swwith quarterly payments. The notionalprincipon the swwill $250,000,000,anthe annualizeswrate is 0.016792. Whitney’s first task is totermine the appropriate swrate.Ninety ys have passesinWhitney’sinitimeetings, anin the interim interest rates have increaseramatically. Whitney’s clients have asketo meet with her to review theirpositions.In orr to prepare for the meeting,Whitney hobtaineupteinterest rate ta this presentein Exhibit 2.Exhibit2 Term Structure of Rates 90 ys Later (%)Using ta in Exhibit 2 ana 30/360 ycount, the market value of Novatel’s swafter 90 ys is closest to: A.–$3,702,900. B.–$2,875,000. C.–$2,408,880. Thepresent value factors for Exhibit 2 are provibelow:For example, PV(180) is calculateas:11+0.0262×(180/360)=0.987069\frac1{1+0.0262\times(180/360)}=0.9870691+0.0262×(180/360)1​=0.987069 Other present value factors are calculaten a similmanner. Using the fixerate initially termineor the swanthe current PV factors, the current value of the fixebons:FB=C∑i=1nPVt,ti(1)+PV0,tn=0.004198(0.994505+0.987069+0.972786)+0.972786=0.9851884FB=C\sum_{i=1}^nPV_{t,ti}(1)+PV_{0,t_n}=0.004198(0.994505+0.987069+0.972786)+0.972786=0.9851884FB=C∑i=1n​PVt,ti​(1)+PV0,tn​​=0.004198(0.994505+0.987069+0.972786)+0.972786=0.9851884 The value of the floating rate bonreset is 1. The marketvalue of the pay-floating, receive fixerate swis the value of thefixerate bonless the value of the floating-rate bon or $250,000,000 ×(0.9851884 – 1.000) = –$3,702,900.Using alternative approach, the newfixeswrate woulberFIX=1.0−PV0,tn(1)∑i=1nPV0,tn(1)=1.0−0.972786/0.994505+0.987069+0.972786=0.00921147r_{FIX}=\frac{1.0-PV_{0,t_n}(1)}{\sum_{i=1}^nPV_{0,t_n}(1)}=1.0-0.972786/0.994505+0.987069+0.972786=0.00921147rFIX​=∑i=1n​PV0,tn​​(1)1.0−PV0,tn​​(1)​=1.0−0.972786/0.994505+0.987069+0.972786=0.00921147 Anthe value of the swis thefferenbetween the value the olrate anthe value the new rate, orV=(FS0−FSt)∑i=1nPVt,ti=(0.004198−0.00921147)×(0.9945+0.9871+0.9728)=−0.0148116V=(FS_0-FS_t)\sum_{i=1}^nPV_{t,t_i}=(0.004198-0.00921147)\times(0.9945+0.9871+0.9728)=-0.0148116V=(FS0​−FSt​)∑i=1n​PVt,ti​​=(0.004198−0.00921147)×(0.9945+0.9871+0.9728)=−0.0148116 The swvalue = $250,000,000 × –0.0148116 = –$3,702,900 用老师的画图方法怎么计算这道题目呢?为什么要重新算一遍swrate?

2024-06-09 10:38 1 · 回答

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2024-04-16 11:21 1 · 回答

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2023-10-21 21:41 2 · 回答

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2023-10-07 19:09 1 · 回答

NO.PZ2023020101000014问题如下 Whitney’s first meeting is with Novatel, aUS basecompany thcurrently houtstanng loof $250,000,000 thatcarries a 5.15% fixeinterest rate. Novatel’s managers feel ththe current interestrate on the lois high anthey also believe thinterest rates are poiseo cline. Whitney aises Novatel to enter into a one-yepay-floating Liborreceive-fixeinterest rate swwith quarterly payments. The notionalprincipon the swwill $250,000,000,anthe annualizeswrate is 0.016792. Whitney’s first task is totermine the appropriate swrate.Ninety ys have passesinWhitney’sinitimeetings, anin the interim interest rates have increaseramatically. Whitney’s clients have asketo meet with her to review theirpositions.In orr to prepare for the meeting,Whitney hobtaineupteinterest rate ta this presentein Exhibit 2.Exhibit2 Term Structure of Rates 90 ys Later (%)Using ta in Exhibit 2 ana 30/360 ycount, the market value of Novatel’s swafter 90 ys is closest to: A.–$3,702,900.B.–$2,875,000.C.–$2,408,880. Thepresent value factors for Exhibit 2 are provibelow:For example, PV(180) is calculateas:11+0.0262×(180/360)=0.987069\frac1{1+0.0262\times(180/360)}=0.9870691+0.0262×(180/360)1​=0.987069 Other present value factors are calculaten a similmanner. Using the fixerate initially termineor the swanthe current PV factors, the current value of the fixebons:FB=C∑i=1nPVt,ti(1)+PV0,tn=0.004198(0.994505+0.987069+0.972786)+0.972786=0.9851884FB=C\sum_{i=1}^nPV_{t,ti}(1)+PV_{0,t_n}=0.004198(0.994505+0.987069+0.972786)+0.972786=0.9851884FB=C∑i=1n​PVt,ti​(1)+PV0,tn​​=0.004198(0.994505+0.987069+0.972786)+0.972786=0.9851884 The value of the floating rate bonreset is 1. The marketvalue of the pay-floating, receive fixerate swis the value of thefixerate bonless the value of the floating-rate bon or $250,000,000 ×(0.9851884 – 1.000) = –$3,702,900.Using alternative approach, the newfixeswrate woulberFIX=1.0−PV0,tn(1)∑i=1nPV0,tn(1)=1.0−0.972786/0.994505+0.987069+0.972786=0.00921147r_{FIX}=\frac{1.0-PV_{0,t_n}(1)}{\sum_{i=1}^nPV_{0,t_n}(1)}=1.0-0.972786/0.994505+0.987069+0.972786=0.00921147rFIX​=∑i=1n​PV0,tn​​(1)1.0−PV0,tn​​(1)​=1.0−0.972786/0.994505+0.987069+0.972786=0.00921147 Anthe value of the swis thefferenbetween the value the olrate anthe value the new rate, orV=(FS0−FSt)∑i=1nPVt,ti=(0.004198−0.00921147)×(0.9945+0.9871+0.9728)=−0.0148116V=(FS_0-FS_t)\sum_{i=1}^nPV_{t,t_i}=(0.004198-0.00921147)\times(0.9945+0.9871+0.9728)=-0.0148116V=(FS0​−FSt​)∑i=1n​PVt,ti​​=(0.004198−0.00921147)×(0.9945+0.9871+0.9728)=−0.0148116 The swvalue = $250,000,000 × –0.0148116 = –$3,702,900 为什么不是折到第90天 而是折到0时点?

2023-10-05 15:13 1 · 回答