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410140980 · 2022年11月03日

老师这里的VaR怎么理解定高了

NO.PZ2016070202000002

问题如下:

A large, international bank has a trading book whose size depends on the opportunities perceived by its traders. The market risk manager estimates the one-day VAR, at the 95% confidence level, to be USD 50 million. You are asked to evaluate how good a job the manager is doing in estimating the one-day VAR. Which of the following would be the most convincing evidence that the manager is doing a poor job, assuming that losses are identical and independently distributed (i.i.d.)?

选项:

A.

Over the past 250 days, there are eight exceptions.

B.

Over the past 250 days, the largest loss is USD 500 million.

C.

Over the past 250 days, the mean loss is USD 60 million.

D.

Over the past 250 days, there is no exception.

解释:

D is correct. We should expect (195%)250=12.5{(1-95\%)}250=12.5 exceptions on average. Having eight exceptions is too few, but the difference could be due to luck. Having zero exceptions, however, would be very unusual, with a probability of 95%250, which is very low. This means that the risk manager is providing VAR estimates that are much too high. Otherwise, the largest or mean losses are not directly useful without more information on the distribution of profits.

这题根据置信区间计算平均例外天数是12.5天,如果实际只有0天出现例外,不是说明基金经理表现很好吗

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已采纳答案

pzqa27 · 2022年11月03日

嗨,爱思考的PZer你好:


VaR回测的本质是检测下我们设定的这个VaR工作起来合不合适,本来我们确定了1天的95%的VaR,根据定义,一段时间内应该有5%的损失是击穿我们设定的界限的,但是我们检测后发现没有一天击穿了界限,证明我们设定的这个界限标准太低了,或者说损失设置的高,这样损失是不容易超过我们的界限的,所以我们这个VaR设置的是不好的

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就算太阳没有迎着我们而来,我们正在朝着它而去,加油!

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NO.PZ2016070202000002 问题如下 A large, internationbank ha trang book whose size pen on the opportunities perceiveits trars. The market risk manager estimates the one-y VAR, the 95% confinlevel, to US50 million. You are asketo evaluate how gooa job the manager is ing in estimating the one-y VAR. Whiof the following woulthe most convincing evinththe manager is ing a poor joassuming thlosses are inticaninpenntly stribute(i.i.)? Over the past 250 ys, there are eight exceptions. Over the past 250 ys, the largest loss is US500 million. Over the past 250 ys, the meloss is US60 million. Over the past 250 ys, there is no exception. is correct. We shoulexpe(1−95%)250=12.5{(1-95\%)}250=12.5(1−95%)250=12.5 exceptions on average. Having eight exceptions is too few, but the fferencoule to luck. Having zero exceptions, however, woulvery unusual, with a probability of 95%250, whiis very low. This means ththe risk manager is proving Vestimates thare mutoo high. Otherwise, the largest or melosses are not rectly useful without more information on the stribution of profits. 如题

2023-03-15 11:25 1 · 回答

NO.PZ2016070202000002 Over the past 250 ys, the largest loss is US500 million. Over the past 250 ys, the meloss is US60 million. Over the past 250 ys, there is no exception. is correct. We shoulexpe(1−95%)250=12.5{(1-95\%)}250=12.5(1−95%)250=12.5 exceptions on average. Having eight exceptions is too few, but the fferencoule to luck. Having zero exceptions, however, woulvery unusual, with a probability of 95%250, whiis very low. This means ththe risk manager is proving Vestimates thare mutoo high. Otherwise, the largest or melosses are not rectly useful without more information on the stribution of profits. 老师好,本题解答用的mean=12.5天,作为判断标准;为什么不是用统计量作为判断标准,例如95%的置信区间,统计量算出应该是19.2天(cutoff)。用mean判断和用t统计量判断的区别是什么?谢谢!

2021-08-21 15:41 1 · 回答

NO.PZ2016070202000002 如果说mean值超过了60m 那var值是50m 肯定是说明var低估了呀 那这个模型就不准确了呀

2021-03-05 19:01 1 · 回答

这里的Meloss是Expecteshortfall的意思吗

2020-11-01 14:02 1 · 回答