NO.PZ2018062016000087
问题如下：
A variable obeying normal distribution has a mean of 0.9 and a standard deviation of 1.5. The probability for that variable to fall between 0.9 and 1.2 is:
选项：
A.
7.93%
B.
6.91%.
C.
5.82%.
解释：
A is correct. Firstly, standardize the original normal distribution：Z= （x-0.9)/1.5, so P(0.9 ≤ x ≤ 1.2) = P( 0 ≤ Z ≤ 0.2).
(1.2-0.9)/1.5=0.2, (0.9-0.9)/1.5=0
Based on the given table, N(0) = 0.5000, N(0.2) = 0.5793. P( 0 ≤ Z ≤ 0.2) = 0.5793– 0.5000 = 0.0793 = 7.93%
为什么是用（0.9-0.9）/1.5求z，而不是z=0.9或1.2ne
