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荣 · 2021年10月05日

请问AB如何区分

NO.PZ2021083101000012

问题如下:

Achler and Rivera discuss remaining text wrangling tasks—specifically, which tokens to include in the document term matrix (DTM). Achler divides unique tokens into three groups; a sample of each group is shown in Exhibit 1.

Based on Exhibit 1, which token group has most likely undergone the text preparation and wrangling process?

选项:

A.

Token Group 1

B.

Token Group 2

C.

Token Group 3

解释:

A is correct.

Data preparation and wrangling involve cleansing and organizing raw data into a consolidated format.

Token Group 1 includes n-grams (“not_increas_market, ” “sale_decreas”) and the words that have been converted from their inflected forms into their base word (“increas, ” “decreas”), and the currency symbol has been replaced with a “currencysign” token.

N-gram tokens are helpful for keeping negations intact in the text, which is vital for sentiment prediction. The process of converting inflected forms of a word into its base word is called stemming and helps decrease data sparseness, thereby aiding in training less complex ML models.

B is incorrect because Token Group 2 includes inflected forms of words (“increased, ” “decreased”) before conversion into their base words (known as stems).

Stemming (along with lemmatization) decreases data sparseness by aggregating many sparsely occurring words in relatively less sparse stems or lemmas, thereby aiding in training less complex ML models.

C is incorrect because Token Group 3 includes inflected forms of words (“increased, ” “decreased”) before conversion into their base words (known as stems). In addition, the “EUR” currency symbol has not been replaced with the “currencysign” token and the word “Sales” has not been lowercased.

考点:Unstructured Data Wrangling (Preprocessing)

请问AB如何区分

1 个答案
已采纳答案

星星_品职助教 · 2021年10月08日

同学你好,

题干要求选择出已经做了“text preparation and wrangling process”的group。

从Group 1和2的区别可以看出,差距主要在是group1的increas 和decreas。这是做了stemming的标志。

stemming会使得increase,increased,increasing这三个本质一样的词从原本的被识别为三个特征,变成此时(正确的)只会被识别为是一个特征“increas”。decreas”也是同理。

而B选项(group 2没有做stemming这个步骤),所以只能选择A选项。


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