ahahaha · 2021年07月11日
NO.PZ2018103102000090
问题如下：
Matt has evaluating the value of Company M of $20 per share by using the two stage model. The company has paid a dividend of $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The required rate of return is 8% What`s the long-term growth rate?
选项：
A. 2.00%
B. 2.51%
C. 3.00%
解释：
B is correct.
考点：Two Stage Model
解析：根据公式:
求得gL = 2.51%
请问这道题有用计算器快一点的方法吗？还是只能列出式子之后一步一步算哎
王园圆_品职助教 · 2023年01月28日
嗨，努力学习的PZer你好：
同学你好，前面助教的答案我这里也没看懂
我这里的建议就是分别用计算器算出D1，D2 和D3，由于P0 = D1/（1+r) + D2/(1+r）^2+D3/(1+r)^3 + P3/(1+r)^3,粉色部分全部已知，我们就可以计算出P3
由于P3 = D3*（1+g)/(r-g),本式中也只有g是未知数，最后就可以计算出来g是多少了
没有什么简便的使用计算器的方法哦
如果带答案的话，把三个答案都试一遍计算NPV，也很麻烦很容易出错的
----------------------------------------------就算太阳没有迎着我们而来，我们正在朝着它而去，加油！
NO.PZ2018103102000090 问题如下 Matt hevaluating the value of Company M of $20 per share using the two stage mol. The company hpaia vinof $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The requirerate of return is 8% What`s the long-term growth rate? A.2.00% B.2.51% C.3.00% B is correct.考点Two Stage Mol解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13(1+0.08)t1×(1+0.05)t+(0.08−gL)(1+0.08)31×1.053×(1+gL)求得gL = 2.51% 如题
NO.PZ2018103102000090 问题如下 Matt hevaluating the value of Company M of $20 per share using the two stage mol. The company hpaia vinof $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The requirerate of return is 8% What`s the long-term growth rate? A.2.00% B.2.51% C.3.00% B is correct.考点Two Stage Mol解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13(1+0.08)t1×(1+0.05)t+(0.08−gL)(1+0.08)31×1.053×(1+gL)求得gL = 2.51% =1，=1.05，=1.1025，=1.1576，V3=1.1576*（1+g）/(0.08-g)=20，反算出g=2.09%
NO.PZ2018103102000090问题如下Matt hevaluating the value of Company M of $20 per share using the two stage mol. The company hpaia vinof $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The requirerate of return is 8% What`s the long-term growth rate?A.2.00%B.2.51%C.3.00%B is correct.考点Two Stage Mol解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13(1+0.08)t1×(1+0.05)t+(0.08−gL)(1+0.08)31×1.053×(1+gL)求得gL = 2.51%这句话我的理解是 v1=1 v2=1.05 v3=1.05^2 这明显和答案不一致 感觉很不太能够理解
2.51% 3.00% B is correct. 考点Two Stage Mol 解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13(1+0.08)t1×(1+0.05)t+(0.08−gL)(1+0.08)31×1.053×(1+gL) 求得gL = 2.51%这个题为什么不用H mol？
