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陈颖方 · 2020年03月01日

问一道题:NO.PZ2015120204000044 [ CFA II ]

问题如下:

After applying data transformations, Steele scales the financial data using normalization. She notes that over the full sample dataset, the “Interest Expense” variable ranges from a minimum of 0.2 and a maximum of 12.2, with a mean of 1.1 and a standard deviation of 0.4.

Exhibit 1 Sample of Raw Structured Data Before Cleansing


Based on Exhibit 1, for the firm with ID #3, Steele should compute the scaled value for the “Interest Expense” variable as:

选项:

A.

0.008.

B.

0.083.

C.

0.250.

解释:

B is correct. Steele uses normalization to scale the financial data. Normalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtracted from each observation
(
Xi), and then this value is divided by the difference between the maximum and minimum values of X (Xmax Xmin):
The firm with ID #3 has an interest expense of 1.2. So, its normalized value is calculated as:

Xi(normalized) =(1.2-0.2)/(12.2-0.2)=0.083

为什么不是(1.2-1.1)/0.4=0.25?

2 个答案

星星_品职助教 · 2020年05月27日

     @Bluebiubiu

题干中明确说明“Steele scales the financial data using normalization”,

如果求standardization,题干中就会明确的说求“standardization/standardize”

星星_品职助教 · 2020年03月01日

同学你好,

求“Normalization”用本题的公式,求“standardization”用你写的那个。

Bluebiubiu · 2020年05月27日

题干中哪个词是提示用normalization? 如果是问standardization会是什么题眼?

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NO.PZ2015120204000044 0.083. 0.250. B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation (Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin): The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateas: Xi(normalize =(1.2-0.2)/(12.2-0.2)=0.083 解答说要用normalization来做rescaling,那么stanrzation应该什么时候用呢?

2021-08-23 07:51 1 · 回答

NO.PZ2015120204000044 这个知识点没有找到,请问一下在讲义的哪个位置

2021-03-06 10:11 1 · 回答

0.083. 0.250. B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation (Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin): The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateas: Xi(normalize =(1.2-0.2)/(12.2-0.2)=0.083 请问这道题涉及的知识点是?

2020-11-07 21:28 1 · 回答

0.083. 0.250. B is correct. Steele uses normalization to scale the financitNormalization is the process of rescaling numeric variables in the range of [0, 1]. To normalize variable X, the minimum value (Xmin) is subtractefrom eaobservation (Xi), anthen this value is vithe fferenbetween the maximum anminimum values of X (Xm– Xmin): The firm with I#3 hinterest expense of 1.2. So, its normalizevalue is calculateas: Xi(normalize =(1.2-0.2)/(12.2-0.2)=0.083 是因为题干中没说是正态分布,所以不用mean和标准差求解吗?

2020-02-18 19:20 1 · 回答