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pz-stepsutake · 2020年01月20日

问一道题:NO.PZ2016070202000002

问题如下:

A large, international bank has a trading book whose size depends on the opportunities perceived by its traders. The market risk manager estimates the one-day VAR, at the 95% confidence level, to be USD 50 million. You are asked to evaluate how good a job the manager is doing in estimating the one-day VAR. Which of the following would be the most convincing evidence that the manager is doing a poor job, assuming that losses are identical and independently distributed (i.i.d.)?

选项:

A.

Over the past 250 days, there are eight exceptions.

B.

Over the past 250 days, the largest loss is USD 500 million.

C.

Over the past 250 days, the mean loss is USD 60 million.

D.

Over the past 250 days, there is no exception.

解释:

D is correct. We should expect (195%)250=12.5{(1-95\%)}250=12.5 exceptions on average. Having eight exceptions is too few, but the difference could be due to luck. Having zero exceptions, however, would be very unusual, with a probability of 1(15%)2501-{(1-5\%)}^{250}, which is very low. This means that the risk manager is providing VAR estimates that are much too high. Otherwise, the largest or mean losses are not directly useful without more information on the distribution of profits.

不太理解这道题的点。1) 比如选项A的8个,和basel committee的three zones的5-9个exception是什么关系呢?8个落在yellow的范围之内,不也表示模型不好么?

2) 看了关于选项D的解释,没有exception尽管可能是个小概率,但如事实如此,难道不应该理解成模型很好么?

1 个答案

orange品职答疑助手 · 2020年01月21日

同学你好,这里我们么并不需要去往巴塞尔协议考虑,这边只是对VaR模型的假设检验。题目要求是评价这位市场风险经理做的这个VaR模型好不好,是评估VaR模型的准确性的,它要求的是风控上的精准

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NO.PZ2016070202000002 问题如下 A large, internationbank ha trang book whose size pen on the opportunities perceiveits trars. The market risk manager estimates the one-y VAR, the 95% confinlevel, to US50 million. You are asketo evaluate how gooa job the manager is ing in estimating the one-y VAR. Whiof the following woulthe most convincing evinththe manager is ing a poor joassuming thlosses are inticaninpenntly stribute(i.i.)? Over the past 250 ys, there are eight exceptions. Over the past 250 ys, the largest loss is US500 million. Over the past 250 ys, the meloss is US60 million. Over the past 250 ys, there is no exception. is correct. We shoulexpe(1−95%)250=12.5{(1-95\%)}250=12.5(1−95%)250=12.5 exceptions on average. Having eight exceptions is too few, but the fferencoule to luck. Having zero exceptions, however, woulvery unusual, with a probability of 95%250, whiis very low. This means ththe risk manager is proving Vestimates thare mutoo high. Otherwise, the largest or melosses are not rectly useful without more information on the stribution of profits. 如题

2023-03-15 11:25 1 · 回答

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2022-11-03 14:17 1 · 回答

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2021-08-21 15:41 1 · 回答

NO.PZ2016070202000002 如果说mean值超过了60m 那var值是50m 肯定是说明var低估了呀 那这个模型就不准确了呀

2021-03-05 19:01 1 · 回答

这里的Meloss是Expecteshortfall的意思吗

2020-11-01 14:02 1 · 回答