问题如下图:
选项:
A.
B.
C.
解释:
这里的调和平均数计算和讲义上的不一样,有没有更简洁的,记忆和计算调和平均数的公式?
NO.PZ201612170200000305 问题如下 5. Baseon Exhibit 1 anusing the harmonic meof the peer group forwarP/Es shown in Exhibit 3 a valuation incator, the common shares of Centralino are: A.unrvalue B.fairly value C.overvalue C is correct. The harmonic meis calculatefollows:xH=n∑i=1n(1xi)=5(15.9)+(18.3)+(13.0)+(115.0)+(14.6)=5.5x_H=\frn{\splaystyle\sum_{i=1}^n{(\frac1{x_i})}}=\frac5{{(\frac1{5.9})}+{(\frac1{8.3})}+{(\frac1{3.0})}+{(\frac1{15.0})}+{(\frac1{4.6})}}=5.5xH=i=1∑n(xi1)n=(5.91)+(8.31)+(3.01)+(15.01)+(4.61)5=5.5The forwarP/E for Centralino is €50/€6.00 = 8.3. Because Centralino’s forwarP/E is higher ththe harmonic meof the peer group, the shares of Centralino apperelatively overvalue 5.5和8.3是算出来了,但不会比较,P/E比率越小越好?
NO.PZ201612170200000305 The forwarP/E for Centralino is €50/€6.00 = 8.3 这里的€6.00找不到?
NO.PZ201612170200000305 我计算的5/(0.17+0.12+0.33+0.667+0.22),为什么算不出5.5
justifieforwarPE 和 普通的forwarPE如何区别?
老师,这个调和平均数的求法是每股都买一块钱的意思来求的是么?我记得上课老师讲的是每只股票都买一股,这好像不太一样呀