FCFF

NO.PZ2018103102000119 问题如下 Matt is preparing to calculate the intrinsic value of Company M’s equity using the FCFF mol with the constant growth rate of 5% infinitely. The most recent FCFF is $2,000 million anthe company is in the 30% tbracket. The relevant information is shown in the following table. Wh`s the value of Company M? A.$ 96,153.85million B.$ 107,836.20million C.$$101,204.82 million C is correct.考点Valuation Mols解析先计算WA= w× r× (1–T) + (wp × rp) + (we × re) = (15,000/40,000)(0.06)(1– 0.3) + (5,000/40,000)(0.04) + (20,000/40,000)(0.1)= 7.075%V=FCFF0×(1+g)WACC−g=2,000×1.057.075%−5%=$101,204.82millionV=\frac{FCFF_0\times\left(1+g\right)}{WACC-g}=\frac{2,000\times1.05}{7.075\%-5\%}=\$101,204.82million V=WACC−gFCFF0​×(1+g)​=7.075%−5%2,000×1.05​=$101,204.82million WA= w× r× (1–T) + (wp × rp) + (we × re)，这个公式没见过，不敢用。那是不是，equity value=firm value--优先股 value?

NO.PZ2018103102000119 如图

NO.PZ2018103102000119

NO.PZ2018103102000119 $ 100,836.20million $100,961.54 million C is correct. 考点Valuation Mols 解析先计算WA= w× r× (1–T) + (wp × rp) + (we × re) = (15,000/40,000)(0.06)(1– 0.3) + (5,000/40,000)(0.04) + (20,000/40,000)(0.1) = 7.08% V=FCFF0×(1+g)WACC−g=2,000×1.057.08%−5%=$100,961.54millionV=\frac{FCFF_0\times\left(1+g\right)}{WACC-g}=\frac{2,000\times1.05}{7.08\%-5\%}=\$100,961.54million V=WACC−gFCFF0​×(1+g)​=7.08%−5%2,000×1.05​=$100,961.54million算WACC时,优先股不需要1—t吗