开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

hillock1122 · 2020年02月05日

问一道题:NO.PZ2016070202000002 [ FRM II ]

问题如下:

A large, international bank has a trading book whose size depends on the opportunities perceived by its traders. The market risk manager estimates the one-day VAR, at the 95% confidence level, to be USD 50 million. You are asked to evaluate how good a job the manager is doing in estimating the one-day VAR. Which of the following would be the most convincing evidence that the manager is doing a poor job, assuming that losses are identical and independently distributed (i.i.d.)?

选项:

A.

Over the past 250 days, there are eight exceptions.

B.

Over the past 250 days, the largest loss is USD 500 million.

C.

Over the past 250 days, the mean loss is USD 60 million.

D.

Over the past 250 days, there is no exception.

解释:

D is correct. We should expect (195%)250=12.5{(1-95\%)}250=12.5 exceptions on average. Having eight exceptions is too few, but the difference could be due to luck. Having zero exceptions, however, would be very unusual, with a probability of 1(15%)2501-{(1-5\%)}^{250}, which is very low. This means that the risk manager is providing VAR estimates that are much too high. Otherwise, the largest or mean losses are not directly useful without more information on the distribution of profits.

C选项,过去250天的平均损失为60M,是指仅仅平均了损失的部分,而不是平均了全部250天的收益和损失部分,对吗?如果250天的均值为60M,是不是也会说明模型不好?

1 个答案

品职答疑小助手雍 · 2020年02月06日

同学你好,不能,这个var的模型还是以次数来定好坏的,即使平均每天损失60M,如果这60M*250都是在一次损失的也只能算一次。所以B和C选项其实是无法判断的。

vivian_zm · 2020年02月11日

请问C选项不是说mean loss吗,我理解就是平均值,不太理解您这里说的60m*250怎在一次发生呢?return的平均值照理应该是小于var(50m),现在为60m也说明模型不对吧

品职答疑小助手雍 · 2020年02月11日

只要有例外就不行哈,比如我一年中249天都没损失,一天损失了60*250=15000m,这样平均下来虽然均值60m,但是过去250天里损失超过var只有一次,按次数来说这个var值还算是定高了。所以落脚点是我解析里的第一句话,是以次数来定好坏的不是以损失量。

  • 1

    回答
  • 1

    关注
  • 382

    浏览
相关问题

NO.PZ2016070202000002 问题如下 A large, internationbank ha trang book whose size pen on the opportunities perceiveits trars. The market risk manager estimates the one-y VAR, the 95% confinlevel, to US50 million. You are asketo evaluate how gooa job the manager is ing in estimating the one-y VAR. Whiof the following woulthe most convincing evinththe manager is ing a poor joassuming thlosses are inticaninpenntly stribute(i.i.)? Over the past 250 ys, there are eight exceptions. Over the past 250 ys, the largest loss is US500 million. Over the past 250 ys, the meloss is US60 million. Over the past 250 ys, there is no exception. is correct. We shoulexpe(1−95%)250=12.5{(1-95\%)}250=12.5(1−95%)250=12.5 exceptions on average. Having eight exceptions is too few, but the fferencoule to luck. Having zero exceptions, however, woulvery unusual, with a probability of 95%250, whiis very low. This means ththe risk manager is proving Vestimates thare mutoo high. Otherwise, the largest or melosses are not rectly useful without more information on the stribution of profits. 如题

2023-03-15 11:25 1 · 回答

NO.PZ2016070202000002 问题如下 A large, internationbank ha trang book whose size pen on the opportunities perceiveits trars. The market risk manager estimates the one-y VAR, the 95% confinlevel, to US50 million. You are asketo evaluate how gooa job the manager is ing in estimating the one-y VAR. Whiof the following woulthe most convincing evinththe manager is ing a poor joassuming thlosses are inticaninpenntly stribute(i.i.)? Over the past 250 ys, there are eight exceptions. Over the past 250 ys, the largest loss is US500 million. Over the past 250 ys, the meloss is US60 million. Over the past 250 ys, there is no exception. is correct. We shoulexpe(1−95%)250=12.5{(1-95\%)}250=12.5(1−95%)250=12.5 exceptions on average. Having eight exceptions is too few, but the fferencoule to luck. Having zero exceptions, however, woulvery unusual, with a probability of 95%250, whiis very low. This means ththe risk manager is proving Vestimates thare mutoo high. Otherwise, the largest or melosses are not rectly useful without more information on the stribution of profits. 这题根据置信区间计算平均例外天数是12.5天,如果实际只有0天出现例外,不是说明基金经理表现很好吗

2022-11-03 14:17 1 · 回答

NO.PZ2016070202000002 Over the past 250 ys, the largest loss is US500 million. Over the past 250 ys, the meloss is US60 million. Over the past 250 ys, there is no exception. is correct. We shoulexpe(1−95%)250=12.5{(1-95\%)}250=12.5(1−95%)250=12.5 exceptions on average. Having eight exceptions is too few, but the fferencoule to luck. Having zero exceptions, however, woulvery unusual, with a probability of 95%250, whiis very low. This means ththe risk manager is proving Vestimates thare mutoo high. Otherwise, the largest or melosses are not rectly useful without more information on the stribution of profits. 老师好,本题解答用的mean=12.5天,作为判断标准;为什么不是用统计量作为判断标准,例如95%的置信区间,统计量算出应该是19.2天(cutoff)。用mean判断和用t统计量判断的区别是什么?谢谢!

2021-08-21 15:41 1 · 回答

NO.PZ2016070202000002 如果说mean值超过了60m 那var值是50m 肯定是说明var低估了呀 那这个模型就不准确了呀

2021-03-05 19:01 1 · 回答

这里的Meloss是Expecteshortfall的意思吗

2020-11-01 14:02 1 · 回答