问题如下图:
选项:
A.
B.
C.
解释:
这道题用:FV=100、 PMT=3、I/Y=2.5、N=5得出PV=102.32
102.32*(1+2.5%)<60/180=103.16
103.16-102.32=0.85
这么做为什么不对呢?
NO.PZ2018062006000070 问题如下 Toy is 5 June 2013. A three-yesemi-annubonwith a coupon rate of 6% just paiits first coupon payment. The pvalue is 100. The interest payment tes are 5 April an5 October. The yielto-maturity equals to 5%. If y count convention is 30/360, calculate the accrueinterest of this Bonon 5 June 2013 A.1.3 0.8 C.1.0 C is correct.The number of ys between 5 April 2013 antoy (5 June 2013) is 60 ys baseon the 30/360 y count convention.Accrueinterest=100×3%×(60/180)=1考点accrueinterest解析accrueinterest=coupon×t/T=(6/2)×(60/180)=1,T代表的就是两个付息日之间的时间间隔,即T=180;t代表的是上个付息日到交易日之间的时间间隔,即t=60。故C正确。 看题目的计算方法100*3%*(60/180),像是单里的计算方法,此处为何不用复利,谢谢。
NO.PZ2018062006000070 count convention is 30/360这条条件的意思 & 用途是怎样的呢
T是coupon perio 也就是两个付息日之间的间隔对么?
老师这道题能不能一下采用的方法
0.8 1.0 C is correct. The number of ys between 5 April 2013 antoy (5 June 2013) is 60 ys baseon the 30/360 y count convention. Accrueinterest=100×3%×(60/180)=1 请问为什么N不是6呢?