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梦梦 · 2024年05月22日

EWMA和GARCH的covariance

NO.PZ2019040801000027

问题如下:

The price percent changes of stock X and Y were 5.0% and 1.0%, respectively. The correlation estimate based on the historical data of the two on day n-1 is 0.6, the estimated standard deviations of price of X and Y on day n-1 were 2.3% and 1.7%, respectively. Suppose the analyst uses the EWMA model with λ = 0.97 to update the correlation and covariance. What is the new estimate of the correlation between X and Y on day n?

选项:

A.

0.34.

B.

0.42.

C.

0.60.

D.

0.68.

解释:

C is correct.

考点:EWMA模型

解析:先计算day n-1时候的协方差:

cov(X, Y) = ΡX,Y x σXσY = 0.6 * 2.3% * 1.7% = 0.000235

然后通过EWMA模型

估计day n的协方差:covn = 0.97 * 0.000235 + 0.03 * 5% * 1% = 0.00024295

估计X的方差:σ2X,n = 0.97 x 0.023^2 + 0.03 x 0.05^2 = 0.00058813

X的标准差就是0.00058813^0.5=0.02425

估计Y的方差:σ2Y,n = 0.97 x 0.0172 + 0.03 x0.012 = 0.0003078 + 0.000003 = 0.0002833

Y的标准差就是0.0002833^0.5=0.01683

最后新的相关系数就是协方差除以X标准差再除以Y的标准差:

0.00024295/(0.02425*0.01683)=0.5952


老师好,请问EWMA和GARCH的covariance是在课程哪里讲的呢?看了下笔记和课程没找到。

梦梦 · 2024年05月23日

好的

1 个答案

品职答疑小助手雍 · 2024年05月22日

同学你好,目前讲义里没有了,原版书valuation那本里面第36页很小的篇幅写了一个cov的计算,公式的基础规则和volatility差不多,改一个字母即可。

YI YU · 2024年10月15日

老师好,请问公式里面的Xn-1和Yn-1代表什么呢? 可以给一个例子吗? 另外,请新的correlation不应该从新求一个Cov (n)然后再求correlation (n)吗,为什么能直接用COV(n-1)来算呢

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