开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

CC · 2024年02月18日

第一问3.01怎么算的

NO.PZ2020010304000016

问题如下:

Suppose that the annual profit of two firms, one an incumbent (Big Firm, X1) and the other a startup (Small Firm, X2), can be described with the following probability matrix:

What are the conditional expected profit and conditional standard deviation of the profit of Big Firm when Small Firm either has no profit or loses money (X2 0)?

选项:

A.

3.01; 30.52

B.

3.01; 931

C.

1.03; 30.52

D.

1.03; 931.25

解释:

We need to compute the conditional distribution given X2 ≤ 0. The relevant rows of the probability matrix are

The conditional distribution can be constructed by summing across rows and then normalizing to sum to unity. The non-normalized sum and the normalized version are

Finally, the conditional expectation is E[X1|X2 ≤0] = Σx1Pr(X1 = x1|X2 ≤0) = USD 3.01M.

The conditional expectation squared is E[X1^2|X2 ≤0]=940.31, and so

the conditional variance is V[X1] = E[X1^2] - E[X1]^2 =940.31-3.01^2=931.25

and the conditional standard deviation is USD 30.52M.

 E[X1|X2 ≤0] = Σx1Pr(X1 = x1|X2 ≤0) = USD 3.01M

根据公式算出来的是1.5050,是哪里有问题吗?



2 个答案

品职答疑小助手雍 · 2024年02月25日

解析里第二个表格 non-normalized那一列就是没有标准化过的非条件概率,这一列概率加和等于49.89%。

标准化就是把这个49.89%当做全集100%,算那一列的四个概率占全集的多少。所以就是分别用那四个非标准化的概率除以49.89%得到右边那一列标准化的概率。

品职答疑小助手雍 · 2024年02月19日

同学你好,注意提问的开头有一个conditional,也就是说是在大公司的利润已经在0或以下的情况下,小公司收益的期望。所以应该把你写的括号里的概率当做一个全集(100%)来进行标准化后计算。

CC · 2024年02月20日

我的思路也是条件概率,只是没标准化,这还是标准化的问题。懂了,谢谢

王佳 · 2024年02月25日

想问标准化是怎么算出来的?

  • 2

    回答
  • 0

    关注
  • 215

    浏览
相关问题

NO.PZ2020010304000016 问题如下 Suppose ththe annuprofit of two firms, one incumbent (Big Firm, X1) anthe other a startup (Small Firm, X2), cscribewith the following probability matrix:Whare the contionexpecteprofit ancontionstanrviation of the profit of Big Firm when Small Firm either hno profit or loses money (X2 ≤ 0)? A.3.01; 30.52 B.3.01; 931 C.1.03; 30.52 1.03; 931.25 We neeto compute the contionstribution given X2 ≤ 0. The relevant rows of the probability matrix areThe contionstribution cconstructesumming across rows anthen normalizing to sum to unity. The non-normalizesum anthe normalizeversion areFinally, the contionexpectation is E[X1|X2 ≤0] = Σx1Pr(X1 = x1|X2 ≤0) = US3.01M. The contionexpectation squareis E[X1^2|X2 ≤0]=940.31, ansothe contionvarianis V[X1] = E[X1^2] - E[X1]^2 =940.31-3.01^2=931.25anthe contionstanrviation is US30.52M. 如题,我这样计算出的答案S30.43

2024-03-11 17:13 1 · 回答

NO.PZ2020010304000016 问题如下 Suppose ththe annuprofit of two firms, one incumbent (Big Firm, X1) anthe other a startup (Small Firm, X2), cscribewith the following probability matrix:Whare the contionexpecteprofit ancontionstanrviation of the profit of Big Firm when Small Firm either hno profit or loses money (X2 ≤ 0)? A.3.01; 30.52 B.3.01; 931 C.1.03; 30.52 1.03; 931.25 We neeto compute the contionstribution given X2 ≤ 0. The relevant rows of the probability matrix areThe contionstribution cconstructesumming across rows anthen normalizing to sum to unity. The non-normalizesum anthe normalizeversion areFinally, the contionexpectation is E[X1|X2 ≤0] = Σx1Pr(X1 = x1|X2 ≤0) = US3.01M. The contionexpectation squareis E[X1^2|X2 ≤0]=940.31, ansothe contionvarianis V[X1] = E[X1^2] - E[X1]^2 =940.31-3.01^2=931.25anthe contionstanrviation is US30.52M. normalize好像讲义里都没提到

2024-03-03 17:25 2 · 回答

NO.PZ2020010304000016问题如下Suppose ththe annuprofit of two firms, one incumbent (Big Firm, X1) anthe other a startup (Small Firm, X2), cscribewith the following probability matrix:Whare the contionexpecteprofit ancontionstanrviation of the profit of Big Firm when Small Firm either hno profit or loses money (X2 ≤ 0)?A.3.01; 30.52B.3.01; 931C.1.03; 30.521.03; 931.25 We neeto compute the contionstribution given X2 ≤ 0. The relevant rows of the probability matrix areThe contionstribution cconstructesumming across rows anthen normalizing to sum to unity. The non-normalizesum anthe normalizeversion areFinally, the contionexpectation is E[X1|X2 ≤0] = Σx1Pr(X1 = x1|X2 ≤0) = US3.01M. The contionexpectation squareis E[X1^2|X2 ≤0]=940.31, ansothe contionvarianis V[X1] = E[X1^2] - E[X1]^2 =940.31-3.01^2=931.25anthe contionstanrviation is US30.52M.讲义sli 71关于contionexpectation的例题中,storeturn 三个概率加起来也是不到100。但是最后解contionexpectation时也是直接用题目中的概率。请问为什么这道题要Normalize?没搞懂,可以一下吗?

2024-01-17 13:14 1 · 回答

NO.PZ2020010304000016 问题如下 Suppose ththe annuprofit of two firms, one incumbent (Big Firm, X1) anthe other a startup (Small Firm, X2), cscribewith the following probability matrix:Whare the contionexpecteprofit ancontionstanrviation of the profit of Big Firm when Small Firm either hno profit or loses money (X2 ≤ 0)? A.3.01; 30.52 B.3.01; 931 C.1.03; 30.52 1.03; 931.25 We neeto compute the contionstribution given X2 ≤ 0. The relevant rows of the probability matrix areThe contionstribution cconstructesumming across rows anthen normalizing to sum to unity. The non-normalizesum anthe normalizeversion areFinally, the contionexpectation is E[X1|X2 ≤0] = Σx1Pr(X1 = x1|X2 ≤0) = US3.01M. The contionexpectation squareis E[X1^2|X2 ≤0]=940.31, ansothe contionvarianis V[X1] = E[X1^2] - E[X1]^2 =940.31-3.01^2=931.25anthe contionstanrviation is US30.52M. 本题考点为条件期望和条件标准差,涉及期望、标准差计算公式以及条件概率性质。计算步骤如下1、条件期望为 E[X1|X2 ≤0]= Σx1Pr(X1 = x1|X2 ≤0)= Σx1*[Pr(X1 = x1,X2 ≤0)/Pr(X2 ≤0)],依次带入X1取4个概率的数值计算。2、条件标准差为E[X1^2|X2 ≤0]- E[X1|X2 ≤0]^2,其中E[X1^2|X2 ≤0]=Σx1^2*Pr(X1 = x1|X2 ≤0)=Σx1^2*[Pr(X1 = x1,X2 ≤0)/Pr(X2 ≤0)];E[X1|X2 ≤0]^2为计算1的结果。想知道以上思路和计算过程是否正确;整个计算比较繁琐,容易出错,是否有更高效的计算方法?

2024-01-07 16:05 2 · 回答