开发者:上海品职教育科技有限公司 隐私政策详情

应用版本:4.2.11(IOS)|3.2.5(安卓)APP下载

Ning Cui · 2023年02月05日

为什么不是条件概率

NO.PZ2015120604000073

问题如下:

According to the above table, which of the following statements is the most correct?

选项:

A.

If performance of today's bond market is poor, the conditional probability of having good performance of next day's bond market is equal to 0.01.

B.

If performance of today's bond market is poor, the conditional probability of having good performance of next day's bond market is equal to 0.20.

C.

If performance of today's bond market is poor, the conditional probability of having good performance of next day's bond market is equal to 0.50.

解释:

B is correct.

P(good performance of next day/poor performance of today)=0.2, which is shown in the table.

这道题不是说在一个事件发生的前提下,这个事件发生吗?不应该用P(B|A)=P(AB)/P(A)这个公式吗?就是0.2/0.4

1 个答案

星星_品职助教 · 2023年02月06日

同学你好,

注意表格条件。最后一列已经是条件概率了。直接选数就可以,不需要再去计算了。

  • 1

    回答
  • 0

    关注
  • 205

    浏览
相关问题

NO.PZ2015120604000073 问题如下 Accorng to the above table, whiof the following statements is the most correct? A.If performanof toy's bonmarket is poor, the contionprobability of having gooperformanof next y's bonmarket is equto 0.01. B.If performanof toy's bonmarket is poor, the contionprobability of having gooperformanof next y's bonmarket is equto 0.20. C.If performanof toy's bonmarket is poor, the contionprobability of having gooperformanof next y's bonmarket is equto 0.50. B is correct.P(gooperformanof next y/poor performanof toy)=0.2, whiis shown in the table. 04*0.2除以(0.4*0.2+0.4*0.5+0.4*0.3)

2023-02-07 07:24 2 · 回答

NO.PZ2015120604000073 问题如下 Accorng to the above table, whiof the following statements is the most correct? A.If performanof toy's bonmarket is poor, the contionprobability of having gooperformanof next y's bonmarket is equto 0.01. B.If performanof toy's bonmarket is poor, the contionprobability of having gooperformanof next y's bonmarket is equto 0.20. C.If performanof toy's bonmarket is poor, the contionprobability of having gooperformanof next y's bonmarket is equto 0.50. B is correct.P(gooperformanof next y/poor performanof toy)=0.2, whiis shown in the table. (1)请问老师,这段题目如何判断出表达的是条件概率,而不是二叉树(需要相乘)~(2)如果题目答案为相乘形式,即第一天市场poor的概率乘以第二天市场goo概率,请问题干一般如何表达?谢谢老师。

2022-11-12 10:13 1 · 回答

老师可以写一下具体计算过程吗?

2020-11-10 17:47 1 · 回答

不应该是0.4*0.2吗?

2019-09-03 00:26 1 · 回答