问题如下图:
选项:
A.
B.
C.
解释:
方差未知不是用t分布的么NO.PZ2017092702000122问题如下 analyst is examining a large sample with unknown population variance. Whiof the following is the most appropriate test to test the hypothesis ththe historicaverage return on inx is less thor equto 6%? A.One-tailez-test B.Two-tailez-test C.One-taileF-test A is correct.If the population samplehunknown variananthe sample is large, a z-test muse Hypotheses involving \"greater than\" or \"less than\" postulations are one-si(one-taile. In this situation, the null analternative hypotheses are stateH0: μ ≤ 6% anHμ 6%, respectively. A one-tailet-test is also acceptable in this case, anthe rejection region is on the right si of the stribution.检验历史的平均收益是否小于等于6%,这样的假设就是单尾的一个概念且对于检验总体均值而言,(总体)方差已知用z,(总体)方差未知用t,非正态(总体)小样本不可估计。所以选择单尾 z-test 根据口诀总体方差未知用t,这题目不就说总体方差未知吗?怎么又用z?
NO.PZ2017092702000122 Two-tailez-test One-taileF-test A is correct. If the population samplehunknown variananthe sample is large, a z-test muse Hypotheses involving \"greater than\" or \"less than\" postulations are one-si(one-taile. In this situation, the null analternative hypotheses are stateH0: μ ≤ 6% anHμ > 6%, respectively. A one-tailet-test is also acceptable in this case, anthe rejection region is on the right si of the stribution. 检验历史的平均收益是否小于等于6%,这样的假设就是单尾的一个概念 且对于检验总体均值而言,(总体)方差已知用z,(总体)方差未知用t,非正态(总体)小样本不可估计。 所以选择单尾&z-test 已知不才用z吗?未知不是用t吗
NO.PZ2017092702000122 大样本下,如果方差未知,检验均值既可以用T检验,也可以用Z检验。 请问课件哪里哪页
原假设不是我们想要拒绝的吗?题干中说想要检验AR是不是小于等于6%,那Ho应该是AR大于6%,考虑到等号要放在Ho里,那Ho应该是大于等于6%,Ha是小于6%?求解答,感谢!
您好 请问A是比C好嘛?还是说C是有问题的?