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AnnaZ · 2022年09月02日

前面Dealer A已经给了新的报价了,为什么不用?

* 问题详情,请 查看题干

NO.PZ202106160100000103

问题如下:

Using the quotes from Dealer A and B, the triangular arbitrage profit on a transaction of MXN 27,000,000 would be closest to:

选项:

A.

GBP 0.

B.

GBP 5,400.

C.

GBP 10,800.

解释:

A is correct.

Using quotes from Dealer A, she can find

MXNGBP=MXNUSD×USDGBP\frac{MXN}{GBP}=\frac{MXN}{USD}\times\frac{USD}{GBP}

The bid from Dealer A for MXN/GBP is effectively

(MXNGBP)bid=(MXNUSD)bid×(USDGBP)bid{(\frac{MXN}{GBP})}_{bid}={(\frac{MXN}{USD})}_{bid}\times{(\frac{USD}{GBP})}_{bid}

The offer from Dealer A is

(MXNGBP)offer=(MXNUSD)offer×(USDGBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{USD})}_{offer}\times{(\frac{USD}{GBP})}_{offer}

To compare with Dealer B’s quote, she must take the inverse of MXN/GBP, so that she has an offer to sell MXN at a rate of 1/24.7742 = GBP 0.0404 and a bid to purchase MXN at a rate of 1/24.8069 = GBP 0.0403. Dealer A is effectively quoting. Although she can effectively buy pesos more cheaply from Dealer A (GBP 0.0404 from Dealer A, versus GBP 0.0406 from Dealer B), she cannot resell them to Dealer B for a higher price than GBP 0.0403. There is no profit from triangular arbitrage.

考点:Triangular arbitrage

能不能从三角套汇中获利的核心在于能不能实现低买高卖。

首先我们计算出Dealer A处MXN/GBP的报价

(MXNGBP)bid=(MXNUSD)bid×(USDGBP)bid{(\frac{MXN}{GBP})}_{bid}={(\frac{MXN}{USD})}_{bid}\times{(\frac{USD}{GBP})}_{bid}

(MXNGBP)offer=(MXNUSD)offer×(USDGBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{USD})}_{offer}\times{(\frac{USD}{GBP})}_{offer}

把上述形式转换一下可得 GBP/MXN的形式,

ASK: 1/24.7742 = 0.0404GBP/MXN

BID: 1/24.8069 = 0.0403GBP/MXN

注意到,MXN/GBP换成GBP/MXN后,因为标价货币和基础货币的地位对调了,所以取倒数后BID和ASK报价也要变化。 现在我们可以拿Dealer A的报价与Dealer B的报价作比较了。

Dealer B关于GBP/MXN的报价是0.0403/0.0406。可以看到,Dealer A对于MXN报价便宜一些,那么投资者应该首先从Dealer A处以0.0404GBP/MXN的价格买进MXN,然后去Dealer B处卖掉MXN,但是在Dealer B卖掉MXN就要用Dealer B的买价,0.0403。可以直观看到投资者以0.0404价格买入,却以0.0403价格卖出,是没有利润可得的。所以投资者不会去做这笔三角套汇,那么三角套汇的利润自然为0。

文章里Dealer A已经给了新的8hips的spread了,为什么不用新的来计算,还用之前表格里面的呢?考试的话到底以哪个为准?

1 个答案

笛子_品职助教 · 2022年09月04日

嗨,从没放弃的小努力你好:


本题是三角套汇的题目,要求根据dealerA报价的MXN/USD以及GBP/EUR,计算出GBP/MXN的汇率,然后把dealer报价计算出的交叉汇率,以及dealer B报价的GBP/MXN做比较,看有无套利空间。


前面Dealer A已经给了新的报价了,为什么不用?还用之前表格里面的呢?

我们看题目:

表格里的就是dealerA的原始报价。


如果使用修改后的报价,是需要有一个特殊协议的。也就是下文说的,special details



而本题的问题是


问的是使用dealerA的报价,并没有问使用special details后的dealerA报价。


考试的话到底以哪个为准?

当然这道题,在使用哪个报价上,讲得不是很清楚,确实会有一定的歧义。

考试的题目,会非常明确用哪个报价,不会出现这样的歧义。


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NO.PZ202106160100000103问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0.B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式,ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到,MXN/GBP换成GBP/MXN后,因为标价货币和基础货币的地位对调了,所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到,aler A对于MXN报价便宜一些,那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN,然后去aler B处卖掉MXN,但是在aler B卖掉MXN就要用aler B的买价,0.0403。可以直观看到投资者以0.0404价格买入,却以0.0403价格卖出,是没有利润可得的。所以投资者不会去做这笔三角套汇,那么三角套汇的利润自然为0。 比如24.774214原为A的bi但取倒数后是否为ask的价格?如是,可否讲解下原理?不太理解

2023-11-28 09:05 1 · 回答

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式,ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到,MXN/GBP换成GBP/MXN后,因为标价货币和基础货币的地位对调了,所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到,aler A对于MXN报价便宜一些,那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN,然后去aler B处卖掉MXN,但是在aler B卖掉MXN就要用aler B的买价,0.0403。可以直观看到投资者以0.0404价格买入,却以0.0403价格卖出,是没有利润可得的。所以投资者不会去做这笔三角套汇,那么三角套汇的利润自然为0。 转换后alerA的报价是GBP/MXN 0.0403-0.0404,我是用这里的biprice0.0403和aler B的biprice0.0403对比,然后得到结果是0,这样做有没有问题?

2023-11-13 17:07 1 · 回答

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式,ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到,MXN/GBP换成GBP/MXN后,因为标价货币和基础货币的地位对调了,所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到,aler A对于MXN报价便宜一些,那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN,然后去aler B处卖掉MXN,但是在aler B卖掉MXN就要用aler B的买价,0.0403。可以直观看到投资者以0.0404价格买入,却以0.0403价格卖出,是没有利润可得的。所以投资者不会去做这笔三角套汇,那么三角套汇的利润自然为0。 老师,我算出来MXN/GBP是24.7742-24.8069,当转化成GBP/MXN以后,算出来的数据,为什么要把biask的位置也调换呢? 另外按照这个逻辑,算出来alerA 是0.04031-0.04036,alerB 是0.0403-0.0404,这个无法判断说谁便宜吧?怎么判断从哪里买入比较划算呢?

2023-11-07 08:33 1 · 回答

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式,ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到,MXN/GBP换成GBP/MXN后,因为标价货币和基础货币的地位对调了,所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到,aler A对于MXN报价便宜一些,那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN,然后去aler B处卖掉MXN,但是在aler B卖掉MXN就要用aler B的买价,0.0403。可以直观看到投资者以0.0404价格买入,却以0.0403价格卖出,是没有利润可得的。所以投资者不会去做这笔三角套汇,那么三角套汇的利润自然为0。 是否一个aler的买价和卖价同时大于另一个aler,才有套利可能?

2022-12-31 23:56 1 · 回答

NO.PZ202106160100000103 问题如下 Using the quotes from aler A anthe triangularbitrage profit on a transaction of MXN 27,000,000 woulclosest to: A.G0. B.G5,400. C.G10,800. A is correct.Using quotes from aler she cfinXNGBP=MXNUSUSBP\frac{MXN}{GBP}=\frac{MXN}{US\times\frac{US{GBP}GBPMXN​=USXN​×GBPUSThe bifrom aler A for MXN/Gis effectively(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)biThe offer from aler A is(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​To compare with aler B’s quote, she must take the inverse of MXN/GBP, so thshe hoffer to sell MXN a rate of 1/24.7742 = G0.0404 ana bito purchase MXN a rate of 1/24.8069 = G0.0403. aler A is effectively quoting. Although she ceffectively buy pesos more cheaply from aler A (G0.0404 from aler versus G0.0406 from aler B), she cannot resell them to aler B for a higher prithG0.0403. There is no profit from triangularbitrage.考点Triangularbitrage能不能从三角套汇中获利的核心在于能不能实现低买高卖。首先我们计算出aler A处MXN/GBP的报价(MXNGBP)bi(MXNUSbi(USBP)bi(\frac{MXN}{GBP})}_{bi={(\frac{MXN}{US)}_{bi\times{(\frac{US{GBP})}_{bi(GBPMXN​)bi=(USXN​)bi×(GBPUS)bi(MXNGBP)offer=(MXNUSoffer×(USBP)offer{(\frac{MXN}{GBP})}_{offer}={(\frac{MXN}{US)}_{offer}\times{(\frac{US{GBP})}_{offer}(GBPMXN​)offer​=(USXN​)offer​×(GBPUS)offer​把上述形式转换一下可得 GBP/MXN的形式,ASK: 1/24.7742 = 0.0404GBP/MXNBI 1/24.8069 = 0.0403GBP/MXN注意到,MXN/GBP换成GBP/MXN后,因为标价货币和基础货币的地位对调了,所以取倒数后BIASK报价也要变化。 现在我们可以拿aler A的报价与aler B的报价作比较了。aler B关于GBP/MXN的报价是0.0403/0.0406。可以看到,aler A对于MXN报价便宜一些,那么投资者应该首先从aler A处以0.0404GBP/MXN的价格买进MXN,然后去aler B处卖掉MXN,但是在aler B卖掉MXN就要用aler B的买价,0.0403。可以直观看到投资者以0.0404价格买入,却以0.0403价格卖出,是没有利润可得的。所以投资者不会去做这笔三角套汇,那么三角套汇的利润自然为0。 我怎么理解的是要卖出EUR,买入GBP。是要乘以较小的那个数就是(0.9467+14/10000)这个数。难道是我理解错了,有点(+﹏+)~晕了,不知道啥时候用乘法和除法以前的题目都做对了,但是这里怎么错了。

2022-11-11 09:05 1 · 回答