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逢考必过过过过过过 · 2022年06月05日

问一道题:NO.PZ2018103102000090 [ CFA II ]

问题如下:

Matt has evaluating the value of Company M of $20 per share by using the two stage model. The company has paid a dividend of $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The required rate of return is 8% What`s the long-term growth rate?

选项:

A.

2.00%

B.

2.51%

C.

3.00%

解释:

B is correct.

考点:Two Stage Model

解析:根据公式: 20=t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}

求得gL = 2.51%

这个题为什么不用H model?
1 个答案

王园圆_品职助教 · 2022年06月05日

嗨,从没放弃的小努力你好:


同学你好,要看题干再做题哦~~“ by using the two stage model”这是题干中的原话——意思就是使用一般的两阶段DDM计算即可

如果要要用Hmodel计算,题目会明确说,或者给出“公司的g是呈线性下降的”这样的条件的哦

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努力的时光都是限量版,加油!

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NO.PZ2018103102000090 问题如下 Matt hevaluating the value of Company M of $20 per share using the two stage mol. The company hpaia vinof $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The requirerate of return is 8% What`s the long-term growth rate? A.2.00% B.2.51% C.3.00% B is correct.考点Two Stage Mol解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13​(1+0.08)t1×(1+0.05)t​+(0.08−gL​)(1+0.08)31×1.053×(1+gL​)​求得gL = 2.51% 如题

2024-01-17 04:29 1 · 回答

NO.PZ2018103102000090 问题如下 Matt hevaluating the value of Company M of $20 per share using the two stage mol. The company hpaia vinof $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The requirerate of return is 8% What`s the long-term growth rate? A.2.00% B.2.51% C.3.00% B is correct.考点Two Stage Mol解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13​(1+0.08)t1×(1+0.05)t​+(0.08−gL​)(1+0.08)31×1.053×(1+gL​)​求得gL = 2.51% =1,=1.05,=1.1025,=1.1576,V3=1.1576*(1+g)/(0.08-g)=20,反算出g=2.09%

2023-09-19 21:32 2 · 回答

NO.PZ2018103102000090问题如下Matt hevaluating the value of Company M of $20 per share using the two stage mol. The company hpaia vinof $1 per share for the most recent year. The relative highly growth rate is 5% over the first three years. The requirerate of return is 8% What`s the long-term growth rate?A.2.00%B.2.51%C.3.00%B is correct.考点Two Stage Mol解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13​(1+0.08)t1×(1+0.05)t​+(0.08−gL​)(1+0.08)31×1.053×(1+gL​)​求得gL = 2.51%这句话我的理解是 v1=1 v2=1.05 v3=1.05^2 这明显和答案不一致 感觉很不太能够理解

2022-07-31 11:14 1 · 回答

NO.PZ2018103102000090 2.51% 3.00% B is correct. 考点Two Stage Mol 解析根据公式: 20=∑t=131×(1+0.05)t(1+0.08)t+1×1.053×(1+gL)(0.08−gL)(1+0.08)320=\sum_{t=1}^3\frac{1\times\left(1+0.05\right)^t}{\left(1+0.08\right)^t}+\frac{1\times1.05^3\times\left(1+g_L\right)}{\left(0.08-g_L\right)\left(1+0.08\right)^3}20=∑t=13​(1+0.08)t1×(1+0.05)t​+(0.08−gL​)(1+0.08)31×1.053×(1+gL​)​ 求得gL = 2.51%请问这道题有用计算器快一点的方法吗?还是只能列出式子之后一步一步算哎

2021-07-11 17:44 2 · 回答